What is your weight in kilograms if you weigh 155 pounds? (1 kg = 2.2 lbs)
The correct Answer and Explanation is :
To convert weight from pounds to kilograms, you can use the conversion factor where 1 kilogram is approximately equal to 2.2 pounds. To find the weight in kilograms when you weigh 155 pounds, you can use the following formula:
[
\text{Weight in kg} = \frac{\text{Weight in lbs}}{2.2}
]
Plugging in the weight:
[
\text{Weight in kg} = \frac{155 \text{ lbs}}{2.2} \approx 70.45 \text{ kg}
]
Thus, if you weigh 155 pounds, your weight in kilograms is approximately 70.45 kg.
Explanation of the Conversion Process
Weight conversion is essential in various fields, including health, nutrition, and fitness. The use of pounds (lbs) is common in the United States and a few other countries, while kilograms (kg) are predominantly used in most parts of the world, especially in scientific contexts. Therefore, knowing how to convert between these units is crucial for effective communication and understanding, particularly in global interactions.
The conversion factor of 2.2 arises from the relationship between pounds and kilograms. Specifically, 1 kg is defined as approximately 2.20462 pounds. For simplicity, 2.2 is often used as an approximation in many practical scenarios.
When performing the conversion, dividing by 2.2 gives a reasonable approximation for most everyday purposes. This method allows for a quick estimate without needing a calculator. However, for precise calculations, using the exact value (2.20462) may be preferable.
In fitness and health assessments, understanding weight in kilograms can be beneficial for body mass index (BMI) calculations, which help assess whether an individual’s weight falls within a healthy range relative to their height. Additionally, converting weights to kilograms is vital in preparing food recipes, dosage calculations in healthcare, and international travel where different weight systems might be used.
In summary, converting 155 pounds to kilograms yields approximately 70.45 kg, illustrating the straightforward relationship between these two measurement systems.