The vapor pressure of water at 0c is 4.579 mmhg what is this pressure in pascals
The Correct Answer and Explanation is :
To convert vapor pressure from millimeters of mercury (mmHg) to pascals (Pa), you can use the conversion factor where 1 mmHg is approximately equal to 133.322 Pa.
Given that the vapor pressure of water at 0°C is 4.579 mmHg, the conversion to pascals can be calculated as follows:
[
\text{Pressure in Pa} = \text{Pressure in mmHg} \times 133.322 \, \text{Pa/mmHg}
]
Substituting in the given value:
[
\text{Pressure in Pa} = 4.579 \, \text{mmHg} \times 133.322 \, \text{Pa/mmHg} \approx 610.34 \, \text{Pa}
]
Thus, the vapor pressure of water at 0°C is approximately 610.34 Pa.
Explanation
Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid at a given temperature. It is a key concept in thermodynamics and physical chemistry, as it indicates how easily a substance can evaporate. At 0°C, water has a vapor pressure of approximately 4.579 mmHg, meaning that at this temperature, water molecules in the liquid state have enough energy to escape into the gaseous state to exert this pressure.
When water is in a closed container at 0°C, some of the molecules will escape from the liquid into the vapor phase. The number of molecules that evaporate increases with temperature, thus increasing vapor pressure. The relationship between temperature and vapor pressure is crucial in many scientific fields, such as meteorology, engineering, and environmental science.
The conversion to pascals (the SI unit for pressure) is necessary for various scientific calculations and engineering applications. One pascal is defined as one newton per square meter, and it provides a standard unit of measure for pressure across different scientific disciplines. Understanding vapor pressure and its conversion helps in various applications, including predicting weather patterns, designing refrigeration systems, and understanding boiling points and phase transitions of substances.