What is the total mass of iron in 1.0 mole of Fe203?
The Correct Answer and Explanation is :
The correct answer is: 111.70 g.
To find the total mass of iron (Fe) in 1 mole of iron(III) oxide (Fe₂O₃), follow these steps:
1. Determine the Molar Mass of Fe₂O₃
The molecular formula for iron(III) oxide is Fe₂O₃, which contains 2 iron (Fe) atoms and 3 oxygen (O) atoms. First, calculate the molar mass of Fe₂O₃ by summing the atomic masses of its elements.
- The atomic mass of iron (Fe) is approximately 55.85 g/mol.
- The atomic mass of oxygen (O) is approximately 16.00 g/mol.
The molar mass of Fe₂O₃ = (2 × 55.85 g/mol) + (3 × 16.00 g/mol)
= 111.70 g/mol (for Fe) + 48.00 g/mol (for O)
= 159.70 g/mol.
2. Calculate the Total Mass of Iron in Fe₂O₃
We know that Fe₂O₃ contains 2 atoms of iron. Since each mole of Fe₂O₃ contains 2 moles of iron atoms, we can calculate the mass of iron in 1 mole of Fe₂O₃ by considering just the iron portion of the molar mass.
- The mass of 2 moles of iron is:
2 × 55.85 g = 111.70 g.
3. Conclusion
The total mass of iron in 1 mole of Fe₂O₃ is 111.70 g.
Explanation:
Iron(III) oxide (Fe₂O₃) is a compound composed of iron and oxygen. To determine the mass of iron in 1 mole of Fe₂O₃, you need to first calculate the molar mass of the entire compound by adding the masses of its constituent atoms. Since Fe₂O₃ contains 2 atoms of iron and 3 atoms of oxygen, the next step is to focus on the mass of iron alone. For every mole of Fe₂O₃, there are 2 moles of iron atoms, which weigh a total of 111.70 grams. This is important in various fields such as chemistry, metallurgy, and environmental science where precise stoichiometric calculations are required for reactions involving iron(III) oxide.