What is the total mass of iron in 1.0 mole of Fe203?
The Correct Answer and Explanation is :
The correct answer is: 111.70 g.
To find the total mass of iron in 1.0 mole of ( \text{Fe}_2\text{O}_3 ) (iron(III) oxide), you first need to calculate the molar mass of ( \text{Fe}_2\text{O}_3 ) and determine the proportion of that mass attributed to iron.
Step-by-Step Calculation:
- Identify Atomic Masses:
- Atomic mass of iron (( \text{Fe} )): ( 55.85 \, \text{g/mol} )
- Atomic mass of oxygen (( \text{O} )): ( 16.00 \, \text{g/mol} )
- Molar Mass of ( \text{Fe}_2\text{O}_3 ):
- The chemical formula ( \text{Fe}_2\text{O}_3 ) consists of 2 iron atoms and 3 oxygen atoms.
- Molar mass of ( \text{Fe}_2\text{O}_3 ):
[
(2 \times 55.85 \, \text{g/mol}) + (3 \times 16.00 \, \text{g/mol}) = 111.70 \, \text{g/mol} + 48.00 \, \text{g/mol} = 159.70 \, \text{g/mol}
]
So, the molar mass of ( \text{Fe}_2\text{O}_3 ) is ( 159.70 \, \text{g/mol} ).
- Mass of Iron in 1 Mole of ( \text{Fe}_2\text{O}_3 ):
Since ( \text{Fe}_2\text{O}_3 ) contains 2 moles of iron atoms, the mass of iron in 1 mole of ( \text{Fe}_2\text{O}_3 ) is:
[
2 \times 55.85 \, \text{g} = 111.70 \, \text{g}
]
Thus, the total mass of iron in 1.0 mole of ( \text{Fe}_2\text{O}_3 ) is 111.70 g.
Explanation:
This calculation is based on the concept of molar mass, which is the mass of 1 mole of a substance. The molar mass of ( \text{Fe}_2\text{O}_3 ) reflects the combined mass of its constituent atoms. In one mole of ( \text{Fe}_2\text{O}_3 ), there are 2 moles of iron atoms and 3 moles of oxygen atoms. By multiplying the atomic masses of these elements by their respective quantities in the compound, you arrive at the molar mass of the compound as a whole.
To isolate the contribution of iron, you consider only the moles of iron within ( \text{Fe}_2\text{O}_3 ), which is 2 moles, and multiply this by the atomic mass of iron, yielding the total iron mass in the compound.