Rewrite the equation in terms of u

Rewrite the equation in terms of u.
(u
2
+3)u−2=0

u
2
u−2=0

(u
2
+9)u−2=0

u
2
u+1=0

The Correct Answer and Explanation is :

It seems there’s a bit of confusion in the way the equations are written here. Let’s clarify and rewrite each one correctly before finding a solution.

Starting with the possible intended equation formats, let’s consider four equations separately:

  1. ((u^2 + 3)u – 2 = 0)
  2. (u^2 \cdot u – 2 = 0)
  3. ((u^2 + 9)u – 2 = 0)
  4. (u^2 \cdot u + 1 = 0)

We’ll go through each equation individually to determine which one could be rewritten and solved.

Equation Analysis:

  1. ((u^2 + 3)u – 2 = 0)
    Expanding this:
    [
    u^3 + 3u – 2 = 0
    ]
    This is a cubic equation in ( u ), and it could potentially have real or complex roots, though solving this would involve either factoring or using numerical methods.
  2. (u^2 \cdot u – 2 = 0)
    Simplifying this, we get:
    [
    u^3 – 2 = 0
    ]
    Solving for ( u ), we find:
    [
    u^3 = 2 \implies u = \sqrt[3]{2}
    ]
    This is a simple solution with a real value.
  3. ((u^2 + 9)u – 2 = 0)
    Expanding this:
    [
    u^3 + 9u – 2 = 0
    ]
    This is another cubic equation, and like the first, it would likely require numerical methods for exact solutions.
  4. (u^2 \cdot u + 1 = 0)
    Simplifying this:
    [
    u^3 + 1 = 0
    ]
    Solving for ( u ), we get:
    [
    u^3 = -1 \implies u = -1
    ]
    since (-1) is the cube root of (-1).

Conclusion

From these, Equation 2: (u^2 \cdot u – 2 = 0) provides a straightforward answer, with ( u = \sqrt[3]{2} ) as the real root. This solution doesn’t require complex factors or additional terms, making it the simplest answer among the options.

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