For each compound, indicate the type (M= molecular, I= ionic, BA= binary acid,OA=oxyacid. Circle each transition metal. Then name each compound SCl4 , HI , BiN , P4S3, Na202
The Correct Answer and Explanation is:
Let’s go through each compound and identify its type, as well as name it, following the instructions you’ve provided. I will also circle the transition metals and provide a detailed explanation.
1. SCl₄
- Type: Molecular (M)
- Explanation:
- This compound is molecular because it consists of two nonmetals: sulfur (S) and chlorine (Cl). Molecular compounds are typically formed between nonmetals, where atoms share electrons. In this case, sulfur forms covalent bonds with four chlorine atoms.
- Name: Sulfur tetrachloride.
2. HI
- Type: Binary Acid (BA)
- Explanation:
- HI is a binary acid because it consists of hydrogen (H) and iodine (I), two elements that form a simple binary compound. When dissolved in water, it ionizes to produce H⁺ ions and I⁻ ions, classifying it as an acid.
- Name: Hydroiodic acid.
3. BiN
- Type: Ionic (I)
- Explanation:
- This compound is ionic because it consists of a metal, bismuth (Bi), and a nonmetal, nitrogen (N). Ionic compounds are formed when metals transfer electrons to nonmetals. Bismuth, a metal, forms a cation (Bi³⁺) while nitrogen forms an anion (N³⁻). They bond through electrostatic attraction.
- Name: Bismuth nitride.
4. P₄S₃
- Type: Molecular (M)
- Explanation:
- This is a molecular compound made up of phosphorus (P) and sulfur (S), both nonmetals. Phosphorus and sulfur form covalent bonds with each other, making this compound molecular in nature.
- Name: Tetraphosphorus trisulfide.
5. Na₂O₂
- Type: Ionic (I)
- Explanation:
- Na₂O₂ is an ionic compound. It consists of sodium (Na), a metal, and oxygen (O), a nonmetal. In this compound, sodium exists as Na⁺ ions and oxygen forms peroxide ions (O₂²⁻). The electrostatic attraction between the cations and anions makes this compound ionic in nature.
- Name: Sodium peroxide.
Summary of the Types:
- Molecular Compounds (M):
- SCl₄ (Sulfur tetrachloride)
- P₄S₃ (Tetraphosphorus trisulfide)
- Ionic Compounds (I):
- BiN (Bismuth nitride)
- Na₂O₂ (Sodium peroxide)
- Binary Acid (BA):
- HI (Hydroiodic acid)
Transition Metals:
- Bismuth (Bi) is a transition metal and is circled in BiN. Transition metals typically occupy the d-block of the periodic table and are often involved in the formation of ionic compounds.
Explanation of Naming Conventions:
- Molecular compounds are named based on the elements involved, with prefixes indicating the number of atoms (tetra for 4, tri for 3, etc.). Example: “Sulfur tetrachloride” for SCl₄.
- Binary acids are named using the prefix “hydro-” followed by the nonmetal’s name with an “-ic” suffix. Example: “Hydroiodic acid” for HI.
- Ionic compounds follow the naming rule where the metal’s name is written first, followed by the nonmetal with an “-ide” suffix (unless it’s a polyatomic ion). Example: “Bismuth nitride” for BiN.
Each compound has a unique naming convention based on its type (molecular, ionic, acid), and these classifications help in understanding their properties and structure.