What is the net ionic equation of 2h+ + so42- + ca2+ + 2i- caso4 + 2h+ + 2i-?
The Correct Answer and Explanation is:
The given equation is:
[ 2H^+ + SO_4^{2-} + Ca^{2+} + 2I^- \rightarrow CaSO_4 + 2H^+ + 2I^- ]
To find the net ionic equation, we need to eliminate the spectator ions—those that remain unchanged on both sides of the equation—and focus only on the species that undergo chemical change.
Step 1: Identify the complete ionic equation
This is the complete ionic equation as written:
[ 2H^+ (aq) + SO_4^{2-} (aq) + Ca^{2+} (aq) + 2I^- (aq) \rightarrow CaSO_4 (s) + 2H^+ (aq) + 2I^- (aq) ]
Step 2: Identify the spectator ions
Spectator ions are ions that appear on both sides of the equation in the same form. In this case, we see that ( 2H^+ ) and ( 2I^- ) appear on both the left and right sides of the equation, so they do not participate in the reaction and are considered spectator ions.
Step 3: Remove the spectator ions
We remove the spectator ions from both sides of the equation:
[ SO_4^{2-} (aq) + Ca^{2+} (aq) \rightarrow CaSO_4 (s) ]
Step 4: Final Net Ionic Equation
After removing the spectator ions, the net ionic equation is:
[ Ca^{2+} (aq) + SO_4^{2-} (aq) \rightarrow CaSO_4 (s) ]
Explanation:
This reaction represents the precipitation of calcium sulfate (( CaSO_4 )) from its ions in solution. Calcium ions (( Ca^{2+} )) and sulfate ions (( SO_4^{2-} )) combine to form solid calcium sulfate, which precipitates out of the solution. The ( H^+ ) and ( I^- ) ions do not participate in the formation of the precipitate and remain unchanged throughout the reaction, hence they are spectator ions.
This type of reaction is a double displacement or precipitation reaction, where two soluble ionic compounds in solution react to form an insoluble product (precipitate). In this case, ( CaSO_4 ) is the precipitate.