6CO2 + 6H20 → C,H120, + 602
- How many molecules of CO2 are presenta
- How many atoms of oxygen are present in the reactants?
- How many atoms of carbon are present in the products
- How many total atoms are present in C.H120,?
- Is the equation above balanced or unbalanced?
The Correct Answer and Explanation is :
Let’s break this down step by step:
Given Equation:
[ 6CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2 ]
6. How many molecules of CO₂ are present?
From the equation, there are 6 molecules of ( CO_2 ) in the reactants.
7. How many atoms of oxygen are present in the reactants?
- ( CO_2 ): Each molecule has 2 oxygen atoms, and there are 6 molecules. So, ( 6 \times 2 = 12 ) oxygen atoms.
- ( H_2O ): Each molecule has 1 oxygen atom, and there are 6 molecules. So, ( 6 \times 1 = 6 ) oxygen atoms.
Total oxygen atoms = 12 + 6 = 18 oxygen atoms in the reactants.
8. How many atoms of carbon are present in the products?
- ( C_6H_{12}O_6 ): This molecule contains 6 carbon atoms.
Total carbon atoms = 6 carbon atoms in the products.
9. How many total atoms are present in ( C_6H_{12}O_6 )?
- Carbon: 6 atoms
- Hydrogen: 12 atoms
- Oxygen: 6 atoms
Total = 6 + 12 + 6 = 24 atoms in ( C_6H_{12}O_6 ).
10. Is the equation balanced or unbalanced?
The equation is balanced.
Explanation:
- On the reactants side:
- Carbon: ( 6 ) (from ( 6CO_2 ))
- Hydrogen: ( 12 ) (from ( 6H_2O ))
- Oxygen: ( 18 ) (( 12 ) from ( CO_2 ) + ( 6 ) from ( H_2O ))
- On the products side:
- Carbon: ( 6 ) (from ( C_6H_{12}O_6 ))
- Hydrogen: ( 12 ) (from ( C_6H_{12}O_6 ))
- Oxygen: ( 18 ) (( 6 ) from ( C_6H_{12}O_6 ) + ( 12 ) from ( 6O_2 ))
Since the number of each type of atom is the same on both sides, the equation is balanced, satisfying the Law of Conservation of Mass. Balancing ensures that no atoms are created or destroyed during the reaction, which is critical in chemical processes. This equation specifically represents photosynthesis, where plants use sunlight to convert carbon dioxide and water into glucose and oxygen, a cornerstone of life on Earth.