About how many drinks does it take for a 200-pound person to reach a 0.02 percent blood alcohol concentration (BAC)?
Answers
One
Two
Three
Four
The Correct Answer and Explanation is :
The correct answer is One.
To explain why, we need to understand how alcohol affects blood alcohol concentration (BAC) and how it varies based on body weight. BAC is the percentage of alcohol in a person’s blood, and it is influenced by factors such as body weight, gender, the type of alcohol consumed, and the time over which alcohol is consumed.
The Widmark formula is often used to estimate BAC:
[
BAC = \frac{{\text{{Alcohol consumed in grams}}}}{{\text{{Body weight in grams}} \times r}} \times 100
]
Where:
- Alcohol consumed in grams is the amount of alcohol in the drink (one standard drink typically contains about 14 grams of pure alcohol),
- Body weight in grams is the person’s weight in grams (a 200-pound person weighs about 90,700 grams),
- r is the alcohol distribution ratio, which is typically 0.68 for men and 0.55 for women.
For a 200-pound male (approximately 90,700 grams), drinking one standard drink (containing 14 grams of alcohol) would likely bring the BAC to around 0.02%. This is a rough estimate, as individual differences, such as metabolic rate and food intake, can affect BAC levels.
Why One Drink?
- A standard drink contains about 14 grams of pure alcohol. For a 200-pound person, consuming this amount typically results in a BAC of about 0.02%.
- If the person consumes more than one drink, their BAC would rise higher, potentially reaching 0.04% with two drinks, 0.06% with three drinks, and so on.
Thus, to reach a BAC of 0.02%, a 200-pound person would generally only need one drink. However, this is a general guideline, and individual variations can play a significant role.