1.) Calculate the molar mass of barium sulfate, BaSO4. a.) 233.4 g/mol b.) 217.4 g/mol c.) 104.0 g/mol d.) 96.0 g/mol 2.) Calculate the molar mass of lead (IV) oxalate, Pb(C2O4)2. a.) 235.21 g/mol b.) 271.24 g/mol c.) 347.21 g/mol d.) 383.24 g/mol 3.) Ethylene glycol is a coolant widely used in automobiles. If its molecular formula is C2H602, how many moles would be present if you had 2500 g of this in your vehicle? a.) 1.6 x 10$ mol b.) 2.5 x 10-2 mol c.) 40. mol d.) 62 mol 4.) Hydrogen peroxide H2O2 is commonly used to clean bacteria in scrapes and cuts. It can be used as a mouthwash and is an additive in some toothpastes. If a sample contained 5.23 x 1021 molecules of H:0, what would the equivalent be in moles? a.) 8.69 x 103 mol b.) 8.69 x 10-mol c.) 115 mol d.) 8.69 x 1043 mol 5.) Calculate the percent composition of ammonium nitrate, NH NO.. a.) 17.5 %N, 5.0%H, 77.5%O b.) 17.5 % N, 3.2% H, 51.6%O c.) 35.0%N, 1.2 % H, 57.2%O d.) None of the above English (United States) Focus LE
The correct answer and explanation is:
Here are the answers with detailed explanations:
1) Molar Mass of Barium Sulfate, BaSO₄
- The atomic masses of the elements are:
- Ba = 137.33 g/mol
- S = 32.07 g/mol
- O = 16.00 g/mol (there are 4 oxygen atoms in BaSO₄)
2) Molar Mass of Lead (IV) Oxalate, Pb(C₂O₄)₂
- The atomic masses of the elements are:
- Pb = 207.2 g/mol
- C = 12.01 g/mol (there are 4 carbon atoms in Pb(C₂O₄)₂)
- O = 16.00 g/mol (there are 8 oxygen atoms in Pb(C₂O₄)₂)
3) Moles of Ethylene Glycol (C₂H₆O₂) in 2500 g
- The atomic masses of the elements are:
- C = 12.01 g/mol (there are 2 carbon atoms in C₂H₆O₂)
- H = 1.008 g/mol (there are 6 hydrogen atoms in C₂H₆O₂)
- O = 16.00 g/mol (there are 2 oxygen atoms in C₂H₆O₂)
4) Moles of Hydrogen Peroxide (H₂O₂) in 5.23 x 10²¹ molecules
- One mole of any substance contains 6.022×10236.022 \times 10^{23} molecules (Avogadro’s number). To convert molecules to moles: Moles=5.23×10216.022×1023=8.69×10−3 mol\text{Moles} = \frac{5.23 \times 10^{21}}{6.022 \times 10^{23}} = 8.69 \times 10^{-3} \, \text{mol} Therefore, the correct answer is b) 8.69 x 10⁻³ mol.
5) Percent Composition of Ammonium Nitrate, NH₄NO₃
- The atomic masses of the elements are:
- N = 14.01 g/mol (there are 2 nitrogen atoms in NH₄NO₃)
- H = 1.008 g/mol (there are 4 hydrogen atoms in NH₄NO₃)
- O = 16.00 g/mol (there are 3 oxygen atoms in NH₄NO₃)
- Percent N = 28.0280.052×100≈35.0%\frac{28.02}{80.052} \times 100 \approx 35.0\%
- Percent H = 4.03280.052×100≈5.0%\frac{4.032}{80.052} \times 100 \approx 5.0\%
- Percent O = 48.0080.052×100≈60.0%\frac{48.00}{80.052} \times 100 \approx 60.0\%
Summary of Answers:
- a) 233.4 g/mol
- d) 383.24 g/mol
- c) 40 mol
- b) 8.69 x 10⁻³ mol
- d) None of the above