Which Equation Can Be Used To Solve For B

Which Equation Can Be Used To Solve For B? B = (8) Tan (30 Degree) B = 8/Tan(30 Degree) B = (8) Sin(30 Degree) B = (8) Sin (30 Degree)

The correct answer and explanation is:

The correct equation to solve for BB is:
B=8⋅tan⁡(30∘)B = 8 \cdot \tan(30^\circ)

Explanation:

In trigonometry, the tangent function relates the opposite side of a right triangle to the adjacent side. Specifically:
tan⁡(θ)=oppositeadjacent\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}

Here, θ\theta is the angle, opposite\text{opposite} is the length of the side opposite the angle, and adjacent\text{adjacent} is the length of the side adjacent to the angle. For this problem, the given angle is 30∘30^\circ, the adjacent side has a length of 88, and BB is the opposite side we need to calculate.

From the tangent formula, rearranging for opposite\text{opposite}, we get:
opposite=tan⁡(θ)⋅adjacent\text{opposite} = \tan(\theta) \cdot \text{adjacent}
Substituting θ=30∘\theta = 30^\circ and adjacent=8\text{adjacent} = 8:
B=8⋅tan⁡(30∘)B = 8 \cdot \tan(30^\circ)

Why the Other Equations Are Incorrect:

  1. B=8/tan⁡(30∘)B = 8 / \tan(30^\circ):
    This equation assumes the roles of the opposite and adjacent sides are reversed. Dividing 88 by tan⁡(30∘)\tan(30^\circ) would calculate the hypotenuse or a side not relevant to this context.
  2. B=8⋅sin⁡(30∘)B = 8 \cdot \sin(30^\circ):
    The sine function relates the opposite side to the hypotenuse (sin⁡(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}). Using sine would require 88 to represent the hypotenuse, which it does not.
  3. Repeated B=8⋅sin⁡(30∘)B = 8 \cdot \sin(30^\circ):
    This redundancy reiterates the same incorrect logic about using the sine function.

Therefore, the correct equation is B=8⋅tan⁡(30∘)B = 8 \cdot \tan(30^\circ). Using this formula ensures the calculation aligns with the proper trigonometric relationship for a triangle’s sides.

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