Which species, has the following ground state electron configuration: 1s2 2s2 2p6 3s2 3p6 4s0 3d8 (a) Fe+  (b) Ni (c) Ni2+ (d) Cu2+ÂÂ
Which species, has the following ground state electron configuration: 1s2 2s2 2p6 3s2 3p6 4s0 3d8ÂÂ
(a) Fe+ ÂÂ
(b) NiÂÂ
(c) Ni2+ÂÂ
(d) Cu2+ÂÂ
The Correct Answer and Explanation is :
The correct answer is (c) Ni²⁺.
Explanation:
- Given Configuration:
The electron configuration provided is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d⁸. This means the 4s orbital is empty ((4s^0)), and the 3d subshell has 8 electrons ((3d^8)). - Understanding Electron Configurations:
- In neutral transition metals, electrons first fill the 4s orbital and then the 3d orbital.
- Upon ionization, electrons are removed first from the 4s orbital before the 3d orbital, because the 4s electrons are higher in energy for transition metals.
- Analyzing the Choices:
- (a) Fe⁺ (Iron ion):
Neutral iron ((Fe)) has the configuration (1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶).
(Fe⁺) would lose one electron, resulting in (1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d⁶), which does not match the given configuration. - (b) Ni (Nickel):
Neutral nickel ((Ni)) has the configuration (1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁸).
The 4s orbital is not empty in neutral nickel, so this does not match. - (c) Ni²⁺ (Nickel ion):
Neutral nickel ((Ni)) loses 2 electrons to become (Ni²⁺).
The two electrons are removed from the 4s orbital, leaving (1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d⁸).
This matches the given configuration. - (d) Cu²⁺ (Copper ion):
Neutral copper ((Cu)) has the configuration (1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d¹⁰).
Losing two electrons from (Cu) results in (1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d⁹), not (3d⁸).
- Conclusion:
The configuration (1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d⁸) corresponds to Ni²⁺, making (c) the correct answer.