A. The Andrade equation can be rearranged to:
Select one:
(x) (i)
B. The reaction:
is known as:
a. Double displacement
b. Single displacement
c. Combination
d. Decomposition
Sol99:
The reaction: ${\rm AgNO}_3+{\rm NaCl}\rightarrow{\rm AgCl}+{\rm NaNO}_3$ is a double displacement reaction, also known as a metathesis reaction. In this type of reaction, the cations and anions of two different compounds switch places, resulting in the formation of two new compounds. In this reaction, the silver ion (Ag+) and chloride ion (Cl-) swap places to form silver chloride (AgCl) and sodium nitrate (NaNO3).
The correct answer and explanation is:
Question A: The Andrade Equation
The Andrade equation is commonly used in thermodynamics to describe the temperature dependence of viscosity for liquids. The rearrangement of this equation to solve for a specific parameter typically depends on the desired variable. However, since no further context or explicit rearrangement is provided here, I can assist further if you clarify which parameter or variable you’re interested in isolating.
Question B: Reaction Type Explanation
The given reaction: AgNO3+NaCl→AgCl+NaNO3{\rm AgNO}_3 + {\rm NaCl} \rightarrow {\rm AgCl} + {\rm NaNO}_3
is classified as a double displacement reaction, also known as a metathesis reaction.
Explanation:
In a double displacement reaction, also referred to as a metathesis reaction, the cations and anions of two reactants exchange places to form two new products. This type of reaction generally occurs in aqueous solutions where the ionic compounds dissociate into their respective ions.
In this reaction, silver nitrate (AgNO3)({\rm AgNO}_3) and sodium chloride (NaCl)({\rm NaCl}) are the reactants. Both are ionic compounds that dissociate in water. The silver ion (Ag+)({\rm Ag}^+) and the nitrate ion (NO3−)({\rm NO}_3^-) separate, as do the sodium ion (Na+)({\rm Na}^+) and the chloride ion (Cl−)({\rm Cl}^-).
When these ions recombine, silver chloride (AgCl)({\rm AgCl}) and sodium nitrate (NaNO3)({\rm NaNO}_3) are formed. Silver chloride is an insoluble compound that precipitates out of the solution as a white solid, while sodium nitrate remains dissolved in water.
The overall ionic exchange can be written as: Ag++Cl−→AgCl (precipitate){\rm Ag}^+ + {\rm Cl}^- \rightarrow {\rm AgCl} \, (\text{precipitate}) Na++NO3−→NaNO3 (soluble){\rm Na}^+ + {\rm NO}_3^- \rightarrow {\rm NaNO}_3 \, (\text{soluble})
This reaction is important in chemistry because it demonstrates a precipitation reaction, where an insoluble solid (silver chloride) forms and settles out of the solution. Such reactions are commonly used in qualitative analysis to identify ions in a solution. Additionally, this reaction provides insight into solubility rules, as only certain ionic combinations lead to precipitates, while others remain soluble.
Thus, the correct classification for this reaction is double displacement or metathesis reaction.