On the weak acid/strong base titration curve below

On the weak acid/strong base titration curve below, label the following points. a) The point where the pH corresponds to a solution of the weak acid (HA) in water. b) The point where the pH corresponds to a solution of the conjugate base (A) in water. c) The point where pH = pK.

The Correct Answer and Explanation is :

In a titration of a weak acid (HA) with a strong base, the pH changes as the base is added. The points of interest on the titration curve are:

a) The point where the pH corresponds to a solution of the weak acid (HA) in water:

At the start of the titration, before any base is added, the solution contains only the weak acid (HA) dissolved in water. The pH at this point is determined by the dissociation of the weak acid in water, which is characterized by its acid dissociation constant (Ka). The pH can be calculated using the formula:

pH=12(pKa−log⁡[HA])\text{pH} = \frac{1}{2} \left( \text{pKa} – \log [\text{HA}] \right)

where pKa is the negative logarithm of Ka, and [HA] is the concentration of the weak acid. This point is at the very beginning of the titration curve.

b) The point where the pH corresponds to a solution of the conjugate base (A⁻) in water:

After adding a sufficient amount of the strong base, the weak acid is neutralized, and the solution contains the conjugate base (A⁻) of the weak acid. The pH at this point is determined by the hydrolysis of the conjugate base in water, which is characterized by its base dissociation constant (Kb). The pH can be calculated using the formula:

pH=14−12(pKb−log⁡[A−])\text{pH} = 14 – \frac{1}{2} \left( \text{pKb} – \log [\text{A}^-] \right)

where pKb is the negative logarithm of Kb, and [A⁻] is the concentration of the conjugate base. This point is reached after the equivalence point on the titration curve.

c) The point where pH = pKa:

The pH equals the pKa of the weak acid at the half-equivalence point of the titration. At this stage, half of the weak acid has been neutralized by the strong base, resulting in equal concentrations of the weak acid (HA) and its conjugate base (A⁻). The pH at this point can be calculated using the Henderson-Hasselbalch equation:

pH=pKa+log⁡([A−][HA])\text{pH} = \text{pKa} + \log \left( \frac{[\text{A}^-]}{[\text{HA}]} \right)

Since [A⁻] = [HA] at the half-equivalence point, the equation simplifies to:

pH=pKa\text{pH} = \text{pKa}

This point is typically located at the midpoint of the steep rise in the titration curve.

Understanding these points is crucial for interpreting titration curves and determining the pKa of weak acids. The initial pH reflects the weak acid’s dissociation in water, the half-equivalence point indicates the pKa, and the final pH corresponds to the behavior of the conjugate base in water. These concepts are fundamental in acid-base chemistry and are essential for analyzing titration data.

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