Consider a binomial experiment with n = 20 and p = .70

Consider a binomial experiment with n = 20 and p = .70.

a. Compute f (12).

b. Compute f (16).

c. Compute P(x ≥ 16).

d. Compute P(x ≤ 15).

e. Compute E(x).

f. Compute Var(x) and σ.

The Correct Answer and Explanation is :

In this problem, we’re dealing with a binomial experiment where:

  • ( n = 20 ) (number of trials),
  • ( p = 0.70 ) (probability of success).

The binomial probability mass function (PMF) is given by:

[
f(x) = P(X = x) = \binom{n}{x} p^x (1 – p)^{n – x}
]

Where:

  • ( \binom{n}{x} ) is the binomial coefficient, which can be calculated as ( \frac{n!}{x!(n – x)!} ).
  • ( p^x ) is the probability of getting exactly ( x ) successes.
  • ( (1 – p)^{n – x} ) is the probability of getting exactly ( n – x ) failures.

a. Compute ( f(12) )

To calculate ( f(12) ), use the binomial PMF formula:

[
f(12) = \binom{20}{12} (0.70)^{12} (0.30)^{8}
]

b. Compute ( f(16) )

Similarly, for ( f(16) ):

[
f(16) = \binom{20}{16} (0.70)^{16} (0.30)^{4}
]

c. Compute ( P(x \geq 16) )

To calculate the probability that ( x \geq 16 ), sum the probabilities from ( x = 16 ) to ( x = 20 ):

[
P(x \geq 16) = f(16) + f(17) + f(18) + f(19) + f(20)
]

d. Compute ( P(x \leq 15) )

To calculate the probability that ( x \leq 15 ), sum the probabilities from ( x = 0 ) to ( x = 15 ):

[
P(x \leq 15) = f(0) + f(1) + \cdots + f(15)
]

e. Compute ( E(x) )

The expected value ( E(x) ) for a binomial distribution is given by:

[
E(x) = n \cdot p = 20 \cdot 0.70 = 14
]

f. Compute ( \text{Var}(x) ) and ( \sigma )

The variance ( \text{Var}(x) ) for a binomial distribution is given by:

[
\text{Var}(x) = n \cdot p \cdot (1 – p) = 20 \cdot 0.70 \cdot 0.30 = 4.2
]

The standard deviation ( \sigma ) is the square root of the variance:

[
\sigma = \sqrt{4.2} \approx 2.05
]

Summary

  • ( f(12) ) and ( f(16) ) are computed using the binomial PMF formula.
  • ( P(x \geq 16) ) and ( P(x \leq 15) ) require summing appropriate probabilities.
  • ( E(x) = 14 ) and ( \text{Var}(x) = 4.2 ), with ( \sigma \approx 2.05 ).

These calculations give insight into the expected outcome and variability of the binomial distribution.

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