The net reaction catalyzed by malate dehydrogenase is malate + NAD+ oxaloacetate + NADH + H +

The net reaction catalyzed by malate dehydrogenase is malate + NAD+ oxaloacetate + NADH + H + The standard reduction potentials for the half-reactions are given in the table: Calculate Delta E0′ for the reaction as shown: Delta E0′ = V Calculate Delta G0′: Delta G0 = kcal / mol

The Correct Answer and Explanation is :

The reaction catalyzed by malate dehydrogenase is:

Malate + NAD⁺ ⇌ Oxaloacetate + NADH + H⁺

To calculate the standard change in Gibbs free energy (ΔG°’) and the standard cell potential (ΔE°’) for this reaction, we can use the standard reduction potentials provided for the half-reactions:

  • Oxaloacetate + 2H⁺ + 2e⁻ ⇌ Malate: E°’ = -0.17 V
  • NAD⁺ + H⁺ + 2e⁻ ⇌ NADH: E°’ = -0.32 V

Calculating ΔE°’:

The standard cell potential (ΔE°’) is calculated by subtracting the reduction potential of the oxidation half-reaction from that of the reduction half-reaction:

ΔE°’ = E°’ (reduction) – E°’ (oxidation)

In this reaction, malate is oxidized to oxaloacetate, and NAD⁺ is reduced to NADH. Therefore, the oxidation half-reaction is:

Malate ⇌ Oxaloacetate + 2H⁺ + 2e⁻

The reduction half-reaction is:

NAD⁺ + H⁺ + 2e⁻ ⇌ NADH

Thus, ΔE°’ = (-0.32 V) – (-0.17 V) = -0.15 V

Calculating ΔG°’:

The standard change in Gibbs free energy (ΔG°’) is related to the standard cell potential (ΔE°’) by the equation:

ΔG°’ = -nFΔE°’

Where:

  • n = number of moles of electrons transferred (2 electrons in this reaction)
  • F = Faraday’s constant (96,485 C/mol)
  • ΔE°’ = standard cell potential (in volts)

Substituting the known values:

ΔG°’ = -2 × 96,485 C/mol × (-0.15 V)

ΔG°’ = 28,946 J/mol

Since 1 kcal = 4,184 J, ΔG°’ = 28,946 J/mol ÷ 4,184 J/kcal ≈ 6.9 kcal/mol

Conclusion:

The standard cell potential (ΔE°’) for the malate dehydrogenase reaction is -0.15 V, and the standard change in Gibbs free energy (ΔG°’) is approximately 6.9 kcal/mol.

A negative ΔE°’ indicates that the reaction is non-spontaneous under standard conditions. The positive ΔG°’ value further confirms that the reaction requires energy input to proceed. In biological systems, this reaction is coupled with other reactions to drive the overall metabolic processes.

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