Write the formula for each of the following coordination compounds
a.
b. Sodium tetracyanocadmate
c. Hexaamminecolbalt(III) chloride
d. Diaquadicyanocopper(II)
e. Potassium hexachloropalladate(IV)
f. Diaquabis(ethylenediamine)cobalt(III) perchlorate
g. Ammonium dibromobis(oxalato)chromate(III)
h. Diamminedinitroplatium(II)
i. Rubidium tetracyanozincate
j. Triaquadibromochlorochrominium(III)
k. Pentacarbonyliron(0) 1. Sodium pentacyanocobalate(Il)
m. Hexammineruthenium(III) tetrachloronickelate(II)
n. Barium hexacyanocobalate(III)
o. Diaquabis(ethylenediammine)colbalt(III) sulfate
p. Tetraamminebromochloroplatinum(IV) chloride
The Correct Answer and Explanation is :
Here are the formulas for the coordination compounds you’ve listed, followed by explanations:
a. Sodium tetracyanocadmate
Formula: Na₂[Cd(CN)₄]
Explanation: This is a complex of cadmium (Cd²⁺) with four cyanide (CN⁻) ligands, and sodium (Na⁺) ions as the counterions. The cyanide ions are monodentate ligands.
b. Hexaamminecobalt(III) chloride
Formula: [Co(NH₃)₆]Cl₃
Explanation: This compound features a cobalt (Co³⁺) ion coordinated to six ammonia (NH₃) molecules. The chloride ions (Cl⁻) are the counterions.
c. Diaquadicyanocopper(II)
Formula: [Cu(H₂O)₂(CN)₂]
Explanation: The copper (Cu²⁺) ion is coordinated with two water (H₂O) molecules and two cyanide (CN⁻) ions.
d. Potassium hexachloropalladate(IV)
Formula: K₂[PdCl₆]
Explanation: Palladium (Pd⁴⁺) is coordinated to six chloride (Cl⁻) ions, and the potassium (K⁺) ions balance the charge.
e. Diaquabis(ethylenediamine)cobalt(III) perchlorate
Formula: [Co(H₂O)₂(en)₂]ClO₄₃
Explanation: The cobalt (Co³⁺) is coordinated to two water molecules (H₂O) and two ethylenediamine (en) ligands. Perchlorate (ClO₄⁻) is the counterion.
f. Ammonium dibromobis(oxalato)chromate(III)
Formula: NH₄[Cr(C₂O₄)₂Br₂]
Explanation: The chromium (Cr³⁺) is coordinated to two oxalate (C₂O₄²⁻) ions and two bromide (Br⁻) ions, with ammonium (NH₄⁺) as the counterion.
g. Diamminedinitroplatium(II)
Formula: [Pt(NH₃)₂(NO₂)₂]
Explanation: The platinum (Pt²⁺) is coordinated to two ammonia (NH₃) molecules and two nitrite (NO₂⁻) ions.
h. Rubidium tetracyanozincate
Formula: Rb₂[Zn(CN)₄]
Explanation: The zinc (Zn²⁺) ion is coordinated to four cyanide (CN⁻) ions, with rubidium (Rb⁺) as the counterions.
i. Triaquadibromochlorochrominium(III)
Formula: [Cr(H₂O)₃Br₂Cl]³⁺
Explanation: The chromium (Cr³⁺) ion is coordinated to three water (H₂O) molecules, two bromide (Br⁻) ions, and one chloride (Cl⁻) ion.
j. Pentacarbonyliron(0)
Formula: Fe(CO)₅
Explanation: This is an iron (Fe) complex with five carbon monoxide (CO) ligands.
k. Sodium pentacyanocobalate(II)
Formula: Na₃[Co(CN)₅]
Explanation: Cobalt (Co²⁺) is coordinated to five cyanide (CN⁻) ions, with sodium (Na⁺) ions as counterions.
l. Hexammineruthenium(III) tetrachloronickelate(II)
Formula: [Ru(NH₃)₆][NiCl₄]²⁻
Explanation: The ruthenium (Ru³⁺) is coordinated to six ammonia (NH₃) molecules, and the nickel (Ni²⁺) is coordinated to four chloride (Cl⁻) ions.
m. Barium hexacyanocobalate(III)
Formula: Ba[Co(CN)₆]
Explanation: The cobalt (Co³⁺) ion is coordinated to six cyanide (CN⁻) ions, with barium (Ba²⁺) as the counterion.
n. Diaquabis(ethylenediamine)cobalt(III) sulfate
Formula: [Co(H₂O)₂(en)₂]SO₄₃
Explanation: The cobalt (Co³⁺) is coordinated to two water molecules (H₂O) and two ethylenediamine (en) ligands. The sulfate (SO₄²⁻) ion is the counterion.
o. Tetraamminebromochloroplatinum(IV) chloride
Formula: [Pt(NH₃)₄BrCl]Cl
Explanation: The platinum (Pt⁴⁺) ion is coordinated to four ammonia (NH₃) molecules, with bromide (Br⁻) and chloride (Cl⁻) ions as ligands. One chloride ion acts as the counterion.
These compounds are all coordination complexes, where the central metal ion is surrounded by ligands (molecules or ions) that donate electron pairs to form coordinate covalent bonds.