What is the name of this compound: (NH4)2[VO(C2O4)2]
The Correct Answer and Explanation is :
The correct name for the compound (NH₄)₂[VO(C₂O₄)₂] is Ammonium bis(oxalato)oxidovanadate(V).
Explanation:
- Identifying the Components:
- (NH₄)₂: This represents two ammonium (NH₄⁺) ions, which are cations.
- [VO(C₂O₄)₂]²⁻: This is the complex anion, where vanadium (V) is the central metal ion.
- Oxidation State of Vanadium:
- Oxalate (C₂O₄)²⁻ is a bidentate ligand, and since there are two of them, the total charge contribution from oxalate is -4.
- Oxo (O²⁻) ligand contributes -2.
- Let the oxidation state of vanadium be x.
- The overall charge of the complex ion is -2, so we set up the equation: x+(−2)+2(−2)=−2x + (-2) + 2(-2) = -2 x−6=−2x – 6 = -2 x=+5x = +5
- So, vanadium is in the +5 oxidation state.
- Nomenclature:
- The oxidation state of vanadium is indicated in Roman numerals as (V).
- The oxo ligand (O²⁻) is named as oxidovanadate.
- The oxalate ligands (C₂O₄)²⁻ are named bis(oxalato) since there are two.
- The ammonium cation is written first since it is the counter-ion.
Final Name:
The systematic name of (NH₄)₂[VO(C₂O₄)₂] is Ammonium bis(oxalato)oxidovanadate(V).