Given an int variable k that has already been declared, use a for loop to print a single line consisting of 97 asterisks. Use no variables other than k. (Please use C standard)
The Correct Answer and Explanation is :
To print a single line of 97 asterisks using a for loop in C, with only the variable k declared, you can write:
for (k = 0; k < 97; k++) {
printf("*");
}
printf("\n");
Explanation:
- Initialization (
k = 0;): he loop starts by settingkto 0. This initialization ensures that counting begins from 0, which is standard in C since array indices and many loops start from 0. - Condition (
k < 97;): he loop continues to execute as long askis less than 97. Sincekstarts at 0, the loop will execute 97 times (from 0 to 96). - Increment (
k++): fter each iteration,kis incremented by 1. This incrementation moves the loop towards its termination condition. - Loop Body (
printf("*");): ithin the loop,printf("*");outputs a single asterisk without a newline character. This function call is executed 97 times, resulting in 97 consecutive asterisks on the same line. - Final
printf("\n");: fter the loop concludes,printf("\n");is called to move the cursor to the next line. This ensures that any subsequent output appears on a new line, maintaining proper formatting.
Key Considerations:
- Variable Usage: he problem specifies using only the variable
k. In this solution,kserves as the loop counter, and no additional variables are introduced. - Loop Execution Count: tarting
kat 0 and looping whilekis less than 97 ensures the loop runs exactly 97 times. This approach leverages zero-based counting, which is idiomatic in C programming. - Output Function: he
printffunction is used for output. By omitting the newline character (\n) in the firstprintfcall, all asterisks are printed on the same line. The subsequentprintf("\n");ensures the output cursor moves to the next line after printing the asterisks.
his method efficiently prints a line of 97 asterisks using aforloop and adheres to the constraint of using only the variablek.