Answer the following questions about the Lewis structure for sulfur dichloride, SCl2 The central atom is Blank 1. Fill in the blank, read surrounding text. . There are Blank 2. Fill in the blank, read surrounding text. valence electrons and Blank 3. Fill in the blank, read surrounding text. REDs. There are Blank 4. Fill in the blank, read surrounding text. single covalent bonds, Blank 5. Fill in the blank, read surrounding text. double covalent bonds, and Blank 6. Fill in the blank, read surrounding text. triple covalent bonds. There are Blank 7. Fill in the blank, read surrounding text. ionic bonds. The shape is Blank 8. Fill in the blank, read surrounding text. and the bond angles are about Blank 9. Fill in the blank, read surrounding text. . a. 0 b. 1 c. 2 d. 3 e. 4 f. 5 g. 8 h. 10 i. 12 j. 14 k. 16 l. 18 m. 20 n. 24 o. 26 p. 30 q. 32 r. 34 s. 36 t. bent u. diatomic v. pyramidal w. linear x. monoatomic ions y. tetrahedral z. trigonal planar aa. 109.5o bb. 120o cc. 180o dd. no bond angles, no central atom ee. S ff. Cl gg. P hh. S and Cl ii. Cl and Cl
The Correct Answer and Explanation is :
Let’s break down each part of the question related to the Lewis structure for sulfur dichloride (SCl2):
- The central atom is S (Sulfur). Sulfur is the central atom in this molecule because it is less electronegative than chlorine and can form two single bonds with chlorine atoms.
- There are 18 valence electrons. Sulfur (S) is in Group 16 of the periodic table, so it has 6 valence electrons. Each chlorine (Cl) atom, also in Group 17, has 7 valence electrons. Thus, for SCl2:
[ \text{Valence electrons} = 6 (\text{from S}) + 7 \times 2 (\text{from Cl}) = 6 + 14 = 18 ] - There are 9 REDs (Resonance Electron Density regions). This refers to the number of electron density regions (lone pairs and bonds) around the central atom (S). Sulfur has no lone pairs, while each chlorine has three lone pairs, and there are two bonds.
- There are 2 single covalent bonds. Sulfur forms single bonds with both chlorine atoms.
- There are 0 double covalent bonds. Since sulfur only forms single bonds with the chlorine atoms, no double bonds are involved.
- There are 0 triple covalent bonds. Similarly, there are no triple bonds in SCl2.
- There are 0 ionic bonds. SCl2 is a covalent compound, meaning the atoms share electrons rather than transfer them to form ionic bonds.
- The shape is bent. Sulfur dichloride adopts a bent molecular geometry due to the two lone pairs on sulfur, which cause a repulsion that bends the molecule.
- The bond angles are about 109.5°. The electron geometry is tetrahedral, considering both the bonding and lone pairs. However, due to the lone pairs, the bond angle between the chlorine atoms is slightly less than the ideal tetrahedral angle of 109.5°.
Final answers:
- S
- 18
- 9
- 2
- 0
- 0
- 0
- bent
- 109.5°
Explanation:
Sulfur dichloride (SCl2) follows the octet rule where sulfur shares electrons with two chlorine atoms. The molecule has a bent shape due to the lone pairs on sulfur, which create a repulsive force, causing the bond angle to be slightly less than 109.5°. The Lewis structure shows two bonds between sulfur and chlorine and the lone pairs on sulfur and chlorine. The molecule has a total of 18 valence electrons that are distributed appropriately to give each atom an octet (except for sulfur, which can accommodate more than 8 electrons due to its position in Period 3). Since SCl2 has no double or triple bonds and is a covalent compound, it does not have ionic bonds.