Solve The Separable Differential Equation Dx/Dt = X^2 + 1/49

Solve The Separable Differential Equation Dx/Dt = X^2 + 1/49, And Find The Particular Solution Satisfying The Initial Condition X(0) = -2.

The Correct Answer and Explanation is :

It seems that the image you provided isn’t accessible in this environment, but based on your description of the separable differential equation:

[
\frac{dx}{dt} = x^2 + \frac{1}{49}
]

Let’s proceed to solve it step by step and find the particular solution for the initial condition ( x(0) = -2 ).

Step 1: Separate the variables

We begin by separating the variables (x) and (t). To do this, we rewrite the equation as:

[
\frac{dx}{x^2 + \frac{1}{49}} = dt
]

Step 2: Simplify the left-hand side

The left-hand side involves a rational function in terms of (x). First, we factor out ( \frac{1}{49} ) from the denominator:

[
x^2 + \frac{1}{49} = \frac{49x^2 + 1}{49}
]

So the equation becomes:

[
\frac{dx}{\frac{49x^2 + 1}{49}} = dt
]

Simplifying further:

[
\frac{49dx}{49x^2 + 1} = dt
]

Step 3: Integrate both sides

Now, we integrate both sides. The integral on the left-hand side is a standard form that can be handled using a standard trigonometric substitution. The integral is:

[
\int \frac{49}{49x^2 + 1} dx = \int dt
]

This is a standard integral form where:

[
\int \frac{dx}{a^2 + x^2} = \frac{1}{a} \arctan\left(\frac{x}{a}\right)
]

In our case, ( a = \frac{1}{7} ), so:

[
\int \frac{49}{49x^2 + 1} dx = 7 \arctan(7x)
]

Thus, we now have:

[
7 \arctan(7x) = t + C
]

Step 4: Solve for the constant of integration

Now, we use the initial condition ( x(0) = -2 ) to find the value of the constant ( C ). Substituting ( t = 0 ) and ( x = -2 ) into the equation:

[
7 \arctan(7(-2)) = 0 + C
]

Simplifying:

[
7 \arctan(-14) = C
]

So, ( C = 7 \arctan(-14) ).

Final solution

Thus, the general solution is:

[
7 \arctan(7x) = t + 7 \arctan(-14)
]

To express ( x ) explicitly in terms of ( t ), we solve for ( x ):

[
\arctan(7x) = \frac{t}{7} + \arctan(-14)
]

[
7x = \tan\left(\frac{t}{7} + \arctan(-14)\right)
]

[
x = \frac{1}{7} \tan\left(\frac{t}{7} + \arctan(-14)\right)
]

This is the particular solution satisfying the initial condition ( x(0) = -2 ).

Conclusion:

The solution to the given differential equation, satisfying the initial condition, is:

[
x(t) = \frac{1}{7} \tan\left(\frac{t}{7} + \arctan(-14)\right)
]

This solution describes how ( x ) evolves over time based on the given equation.

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