Complete the following table:
Compound Name
Formula
Magnesium phosphide
AgClO4
Chromium(VI) oxide
P2S5
Silicon tetrafluoride
Ca3(PO4)2
Diiodine trifluoride
Cu2S
The Correct Answer and Explanation is :
Here’s the completed table with the correct chemical formulas for the compounds mentioned:
| Compound Name | Formula |
|---|---|
| Magnesium phosphide | Mg3P2 |
| Silver perchlorate | AgClO4 |
| Chromium(VI) oxide | CrO3 |
| Diphosphorus pentasulfide | P2S5 |
| Silicon tetrafluoride | SiF4 |
| Calcium phosphate | Ca3(PO4)2 |
| Diiodine trifluoride | I2F3 |
| Copper(I) sulfide | Cu2S |
Explanation:
- Magnesium phosphide (Mg3P2): Magnesium phosphide is composed of magnesium (Mg) and phosphorus (P). Since magnesium has a +2 charge and phosphorus has a -3 charge, three magnesium ions (Mg²⁺) are needed to balance two phosphide ions (P³⁻), resulting in the formula Mg3P2.
- Silver perchlorate (AgClO4): Perchlorate is a polyatomic ion with the formula ClO4⁻. Silver (Ag) has a +1 charge, so one silver ion combines with one perchlorate ion to form AgClO4.
- Chromium(VI) oxide (CrO3): Chromium(VI) oxide, also known as chromic acid anhydride, contains chromium with a +6 oxidation state. Oxygen typically has a -2 charge, so three oxygen atoms balance the six positive charges from the chromium, leading to the formula CrO3.
- Diphosphorus pentasulfide (P2S5): Phosphorus and sulfur combine to form this compound. Phosphorus in P2S5 has a +5 oxidation state, and sulfur has a -2 charge. Two phosphorus atoms balance the five sulfur atoms, resulting in P2S5.
- Silicon tetrafluoride (SiF4): Silicon has a +4 charge, and fluoride (F) has a -1 charge. Four fluoride ions balance the charge of one silicon ion, forming SiF4.
- Calcium phosphate (Ca3(PO4)2): Calcium (Ca) has a +2 charge, and the phosphate ion (PO4) has a -3 charge. Three calcium ions balance two phosphate ions, resulting in the formula Ca3(PO4)2.
- Diiodine trifluoride (I2F3): Diiodine trifluoride consists of two iodine (I) atoms and three fluoride (F) atoms. Each iodine atom has a +1 charge, and each fluoride ion has a -1 charge, so the formula is I2F3.
- Copper(I) sulfide (Cu2S): Copper in copper(I) sulfide has a +1 charge, while sulfur has a -2 charge. Two copper ions balance one sulfur ion, resulting in Cu2S.