Methanol has a boiling point of

1. Methanol has a boiling point of . What is this temperature in:
   degrees Fahrenheit?
   F
   Kelvin?
2. If the room has a temperature of , what is the temperature difference between the boiling point and the room temperature in:
   Kelvin?
   Rankine?

The Correct Answer and Explanation is :

1. Methanol Boiling Point Conversion

Methanol has a boiling point of 64.7°C. To convert this to Fahrenheit and Kelvin:

To Fahrenheit:

The formula for converting Celsius to Fahrenheit is:

[
F = \left( \frac{9}{5} \times C \right) + 32
]

Using the boiling point of methanol:
[
F = \left( \frac{9}{5} \times 64.7 \right) + 32 = 148.46°F
]

So, the boiling point of methanol is 148.46°F.

To Kelvin:

The formula for converting Celsius to Kelvin is:

[
K = C + 273.15
]

Using the boiling point of methanol:
[
K = 64.7 + 273.15 = 337.85 \, K
]

So, the boiling point of methanol is 337.85 Kelvin.

---

2. Temperature Difference

Let’s assume the room temperature is 20°C. To find the temperature difference between the boiling point of methanol (64.7°C) and room temperature, we need to calculate the differences in Kelvin and Rankine.

Temperature Difference in Kelvin:

The temperature difference in Kelvin is the same as the difference in Celsius, because both Kelvin and Celsius scales have the same size degree. The difference between the boiling point of methanol and room temperature is:

[
\Delta T_{\text{Kelvin}} = 64.7°C – 20°C = 44.7 \, K
]

So, the temperature difference is 44.7 K.

Temperature Difference in Rankine:

To convert Celsius to Rankine, we first need to convert Celsius to Kelvin and then convert that to Rankine. The formula for converting Kelvin to Rankine is:

[
R = K \times \frac{9}{5}
]

First, we find the temperature in Kelvin for both the boiling point and room temperature:

• Boiling point: ( 64.7°C + 273.15 = 337.85 \, K )
• Room temperature: ( 20°C + 273.15 = 293.15 \, K )

Now, we convert these to Rankine:

• Boiling point in Rankine: ( 337.85 \times \frac{9}{5} = 608.13 \, R )
• Room temperature in Rankine: ( 293.15 \times \frac{9}{5} = 527.67 \, R )

Now, find the difference:

[
\Delta T_{\text{Rankine}} = 608.13 \, R – 527.67 \, R = 80.46 \, R
]

So, the temperature difference is 80.46 Rankine.

Summary:

• Methanol boiling point in Fahrenheit: 148.46°F
• Methanol boiling point in Kelvin: 337.85 K
• Temperature difference in Kelvin: 44.7 K
• Temperature difference in Rankine: 80.46 R

These conversions show how the boiling point of methanol and the temperature difference can be represented in different temperature scales.