Find the projection of u onto v and then find the vector component of u orthogonal to v

 Find the projection of u onto v and then find the vector component of u orthogonal to v. Show the steps of your calculation. Sketch a figure and label u, v, the projection of u onto v and the vector component of u orthogonal to v. u=(2,3) and v=(5,1) proj, (u) = w = vector component of u orthogonal to V=

The Correct Answer and Explanation is :

To solve for the projection of vector u onto vector v, and the vector component of u orthogonal to v, we will follow these steps:

Step 1: Formula for the projection of u onto v

The formula for the projection of vector u onto vector v is given by:

[
\text{proj}_{v}(u) = \frac{u \cdot v}{v \cdot v} v
]

where:

  • ( u \cdot v ) is the dot product of u and v
  • ( v \cdot v ) is the dot product of v with itself, i.e., the squared magnitude of v

Step 2: Calculate the dot products

Given:

  • u = (2, 3)
  • v = (5, 1)

Dot product ( u \cdot v ):

[
u \cdot v = (2)(5) + (3)(1) = 10 + 3 = 13
]

Dot product ( v \cdot v ):

[
v \cdot v = (5)(5) + (1)(1) = 25 + 1 = 26
]

Step 3: Calculate the projection of u onto v

Using the formula:

[
\text{proj}_{v}(u) = \frac{13}{26} v = \frac{1}{2} (5, 1) = \left( \frac{5}{2}, \frac{1}{2} \right)
]

So, the projection of u onto v is ( \left( \frac{5}{2}, \frac{1}{2} \right) ).

Step 4: Calculate the component of u orthogonal to v

The component of u orthogonal to v can be found by subtracting the projection of u onto v from u:

[
w = u – \text{proj}_{v}(u)
]

[
w = (2, 3) – \left( \frac{5}{2}, \frac{1}{2} \right) = \left( 2 – \frac{5}{2}, 3 – \frac{1}{2} \right)
]

[
w = \left( \frac{4}{2} – \frac{5}{2}, \frac{6}{2} – \frac{1}{2} \right) = \left( -\frac{1}{2}, \frac{5}{2} \right)
]

So, the vector component of u orthogonal to v is ( \left( -\frac{1}{2}, \frac{5}{2} \right) ).

Step 5: Conclusion

  • The projection of u onto v is ( \left( \frac{5}{2}, \frac{1}{2} \right) ).
  • The vector component of u orthogonal to v is ( \left( -\frac{1}{2}, \frac{5}{2} \right) ).

Now, let’s create a sketch to visualize this:

I’ll generate a plot with the vectors u, v, the projection of u onto v, and the orthogonal component.

In the plot above, you can see the following:

  • The red vector u = (2, 3).
  • The blue vector v = (5, 1).
  • The green vector represents the projection of u onto v (( \text{proj}_v(u) = \left( \frac{5}{2}, \frac{1}{2} \right) )).
  • The purple vector represents the component of u orthogonal to v (( w = \left( -\frac{1}{2}, \frac{5}{2} \right) )).

This visualization helps to understand how u breaks down into two parts: one parallel to v (the projection) and one orthogonal to v (the orthogonal component).

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