In wild cats, long tails (L) are dominant to bobtails (l). Which genotype(s) give a long-tailed cat? LL ll Ll In Aardvarks, straight hair (S) is dominant to curly hair (s). Two heterozygous Aardvarks (male and female) mate and produce four beautiful offspring. Fill in the Punnet Square below with the correct genotypes of the offspring from this cross. Ss X Ss Set up the Punnett Square for the monohybrid cross that is listed below. The trait being studied is round seeds (dominant) and wrinkled seeds (recessive). Rrx rr In Smileys, eye shape can be starred (SS), circular (CC), or a circle with a star (CS). CC SS CS Imagine a cross between a circle eyed and a circle-star eyed. CC x CS What percentage of the offspring will be circle eyed? What percentage of the offspring will be circle-star-eyed? What percentage of the offspring will be starred eyed?
In wild cats, long tails (L) are dominant to bobtails (l). Which genotype(s) give a long-tailed cat?
Ll In Aardvarks, straight hair (S) is dominant to curly hair (s). Two heterozygous Aardvarks (male and female) mate and produce four beautiful offspring. Fill in the Punnet Square below with the correct genotypes of the offspring from this cross.
Set up the Punnett Square for the monohybrid cross that is listed below. The trait being studied is round seeds (dominant) and wrinkled seeds (recessive). Rrx r
In Smileys, eye shape can be starred (SS), circular (CC), or a circle with a star (CS).
CC SS CS
Imagine a cross between a circle eyed and a circle-star eyed. CC x CS
What percentage of the offspring will be circle eyed?
What percentage of the offspring will be circle-star-eyed?
What percentage of the offspring will be starred eyed?
In humans, the four blood types A, B, O, and AB are determined by three alleles IA, IB, and i.
Write the genotype for each person based on the descriptions given below:
a. Homozygous for the allele
b. Heterozygous for the allele
c. Type O
d. Type and had a type parent
e. Type “AB
f. Blood can be donated to anybody
g. Can only get blood from a type “Oâ€Â� donorÂÂ
Mrs. Essy is type “A� and Mr. Essy is type “O.� They have three children named Matthew, Mark, and Luke. Mark is type “O,� Matthew is type “A,� and Luke is type “AB.� Based on this information:
a. Mr. Essy must have the genotypeÂÂ
b. Mrs. Essy must have the genotype  because  has blood typeÂÂ
c. Luke cannot be the child of these parents because neither parent has the alleleÂÂ
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In garden peas, round seeds (R) are completely dominant to wrinkled seeds (r), and yellow seeds (Y) are completely dominant to green seeds (y). Consider the following dihybrid cross.
Answer the following questions based on the results of this cross shown in the image above.
How many of the offspring are yellow and round?ÂÂ
How many of the offspring are green and wrinkled?ÂÂ
How many of the offspring are yellow and wrinkled?ÂÂ
How many of the offspring are green and round?ÂÂ
How many different phenotypes are possible with this cross?ÂÂ
How many different genotypes are possible in the offspring?ÂÂ
The Correct Answer and Explanation is :
Let’s break this down into several parts:
1. Wild Cats Genotype for Long Tails:
- Long tails (L) are dominant to bobtails (l).
- A long-tailed cat can have the following genotypes:
- LL (homozygous dominant)
- Ll (heterozygous)
2. Punnett Square for Aardvarks (Straight Hair):
- Straight hair (S) is dominant to curly hair (s).
- The two heterozygous aardvarks (Ss x Ss) will create the following Punnett square:
| S | s | |
|---|---|---|
| S | SS | Ss |
| s | Ss | ss |
So, the genotypes of the offspring will be:
- SS (homozygous dominant): 25%
- Ss (heterozygous): 50%
- ss (homozygous recessive): 25%
3. Monohybrid Cross for Round Seeds (R) and Wrinkled Seeds (r):
- Round seeds (R) are dominant to wrinkled seeds (r).
- The cross is Rr x rr. The Punnett square looks like this:
| R | r | |
|---|---|---|
| r | Rr | rr |
| r | Rr | rr |
The offspring will have:
- Rr (heterozygous, round seeds): 50%
- rr (homozygous recessive, wrinkled seeds): 50%
4. Smileys Eye Shape (Starred, Circular, Circle-Star):
- Eye shape can be starred (SS), circular (CC), or a circle with a star (CS).
- The cross between CC x CS will produce the following:
| C | C | |
|---|---|---|
| C | CC | CC |
| S | CS | CS |
The offspring will have:
- CC (circle eyes): 50%
- CS (circle-star eyes): 50%
- SS (starred eyes): 0%
So, the percentages will be:
- Circle-eyed: 50%
- Circle-star-eyed: 50%
- Starred-eyed: 0%
5. Human Blood Types (IA, IB, i):
- a. Homozygous for the allele: Either IAIA or IBIB
- b. Heterozygous for the allele: Either IAi or IBi
- c. Type O: ii
- d. Type A and had a type O parent: IAi
- e. Type AB: IAIB
- f. Blood can be donated to anybody: AB (Universal recipient) with IAIB
- g. Can only get blood from a type “O” donor: O (Universal donor), ii
6. Essy Family Genotype and Blood Types:
- a. Mr. Essy (Type O) must have the genotype ii because he is type O.
- b. Mrs. Essy (Type A) must have the genotype IAi because she has type A and passed on the O allele (i) to her children.
- c. Luke cannot be the child of these parents because neither parent has the IAIB combination necessary to produce type AB blood.
7. Garden Peas (Dihybrid Cross: Round and Yellow Seeds):
- RrYy x RrYy dihybrid cross:
- Round seeds (R) and Yellow seeds (Y) are both dominant to their recessive counterparts.
Punnett Square Outcomes:
- The offspring could have four different phenotypes:
- Yellow and Round: 9/16
- Green and Round: 3/16
- Yellow and Wrinkled: 3/16
- Green and Wrinkled: 1/16
Phenotypes:
- 4 different phenotypes are possible: Yellow and Round, Green and Round, Yellow and Wrinkled, Green and Wrinkled.
Genotypes:
- 9 different genotypes are possible from this dihybrid cross.
If you need to fill in the table from the image you provided, let me know, and I can help you do that!