The Chemical Formula For Barium Sulfide Is Bas. A Chemist Determined By Measurements That 0.085 Moles Of Barium Sulfide Participate In A Chemical Reaction. Calculate The Mass Of Barium Sulfide That Participates Be Sure Your Answer Has The Correct Number Of Significant Digits. D. ?
The Correct Answer and Explanation is :
To calculate the mass of barium sulfide (BaS) that participates in a chemical reaction, we need to follow the steps of converting moles into grams. The formula for this conversion is:
[
\text{Mass} = \text{Moles} \times \text{Molar Mass}
]
Step-by-Step Calculation
- Find the Molar Mass of Barium Sulfide (BaS):
The molar mass of a compound is the sum of the molar masses of its individual elements. From the periodic table:
- The atomic mass of barium (Ba) is approximately 137.33 g/mol.
- The atomic mass of sulfur (S) is approximately 32.07 g/mol. So, the molar mass of BaS is: [
137.33 \, \text{g/mol (Ba)} + 32.07 \, \text{g/mol (S)} = 169.4 \, \text{g/mol}
]
- Use the Given Moles of Barium Sulfide:
The problem states that 0.085 moles of BaS participate in the reaction. - Calculate the Mass:
Now that we know the molar mass of BaS (169.4 g/mol) and the moles of BaS (0.085 moles), we can calculate the mass: [
\text{Mass} = 0.085 \, \text{moles} \times 169.4 \, \text{g/mol} = 14.39 \, \text{grams}
]
Final Answer:
The mass of barium sulfide (BaS) that participates in the reaction is 14.39 grams.
Significant Figures:
- The given data (0.085 moles) has 2 significant digits.
- The molar mass of BaS is given with 4 significant digits, so the final answer should be rounded to 2 significant digits to match the least precise value (0.085 moles).
Thus, the final mass is 14 grams (rounded to two significant digits).
Now, I will generate an image to visualize the chemical reaction and calculations.
Here is the illustration that shows the process of converting moles of Barium Sulfide (BaS) into mass. It includes the calculation steps and labels for clarity.
Let me know if you need any further explanations!
