What do the bond angles of beryllium hydride suggest about the hybridization state of med sin visviso 918 zinq anibnodnion od usodº.
The Correct Answer and Explanation is :
Bond Angles and Hybridization of Beryllium Hydride (BeH₂)
Beryllium hydride (BeH₂) is a simple linear molecule where the bond angle between the hydrogen atoms is 180°. This suggests that the hybridization state of Be in BeH₂ is sp hybridized.
Explanation of Hybridization in BeH₂ (300 Words)
To understand why BeH₂ adopts sp hybridization, let’s analyze its electronic structure and bonding.
- Electronic Configuration of Beryllium:
- The atomic number of Be is 4, and its ground-state electronic configuration is:
1s² 2s² - In this state, Be has a completely filled 2s orbital and an empty 2p orbital, meaning it cannot readily form bonds.
- Promotion and Hybridization:
- To form two Be-H sigma bonds, one of the 2s electrons is promoted to a 2p orbital, resulting in:
1s² 2s¹ 2p¹ - The 2s and one 2p orbital then undergo sp hybridization, forming two equivalent sp hybrid orbitals that are oriented 180° apart.
- Formation of Be-H Bonds:
- Each sp hybrid orbital overlaps with the 1s orbital of hydrogen, forming two sigma bonds.
- Because there are no lone pairs on Be, the molecule maintains a linear shape.
- Why 180° Bond Angle?
- The sp hybrid orbitals arrange themselves as far apart as possible due to electron repulsion, resulting in a linear geometry with a bond angle of 180°.
- Conclusion:
- The bond angles in BeH₂ confirm that beryllium is sp hybridized, forming a linear structure with two sigma bonds and no lone pairs.
Generated Image
I will now generate an image illustrating the molecular structure and hybridization of BeH₂.
Here is the generated molecular diagram of beryllium hydride (BeH₂), illustrating its linear structure, 180° bond angles, and sp hybridization. Let me know if you need any modifications or further explanations!
