comparing CH3Br (polar) and CH4(non-polar)

comparing CH3Br (polar) and CH4(non-polar)

electronegativity

C-Br = 0.3 – no dipole moment

C-H = 0.4 – no dipole moment

how is CH3Br polar? do you add the dipoles facing thesame direction to get 1.5?

The Correct Answer and Explanation is :

Why is CH₃Br Polar While CH₄ is Non-Polar?

Methyl bromide (CH₃Br) is polar, whereas methane (CH₄) is non-polar due to differences in molecular shape and dipole moment summation.

Electronegativity and Dipole Moments

  • Electronegativity values (Pauling scale):
  • Carbon (C) = 2.55
  • Hydrogen (H) = 2.20
  • Bromine (Br) = 2.96
  • Bond Dipoles:
  • C-H bond: Difference = 2.55 – 2.20 = 0.35 (nearly non-polar)
  • C-Br bond: Difference = 2.96 – 2.55 = 0.41 (small dipole, but important)

Despite both electronegativity differences being small (0.3–0.4), what matters is the molecular geometry and how these dipole moments sum up.

Why is CH₄ Non-Polar?

  • CH₄ has a tetrahedral structure with four identical C-H bonds.
  • The small dipoles in each C-H bond cancel out perfectly due to symmetry.
  • This results in zero net dipole moment, making CH₄ non-polar.

Why is CH₃Br Polar?

  • CH₃Br is also tetrahedral, but now one hydrogen is replaced by bromine.
  • The C-Br bond is more polar than the C-H bonds.
  • The dipole moments do not cancel out due to asymmetry.
  • The C-Br dipole points towards bromine, while the weaker C-H dipoles point in different directions.
  • The vector sum of all dipoles gives a net dipole moment towards Br, making CH₃Br polar.

Thus, CH₃Br is polar because the dipoles do not completely cancel, unlike CH₄ where symmetry ensures no net dipole.

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