An operating system uses shortest remaining time first scheduling algorithm for pre emptive scheduling of processes

An operating system uses shortest remaining time first scheduling algorithm for pre emptive scheduling of processes. Consider the following set of processes with their arrival times and execution times (in milliseconds) a) Draw a Gantt chart to represent an order of process execution b) Calculate waiting and turnaround of each process c) Calculate the response time of each process. 4) Compute the average waiting time, average turnaround An operating system uses shortest remaining time first scheduling algorithm for pre emptive scheduling of processes. Consider the following set of processes with their arrival times and execution times (in milliseconds) a) Draw a Gantt chart to represent an order of process execution b) Calculate waiting and turnaround of each process c) Calculate the response time of each process. 4) Compute the average waiting time, average turnaround time

Process
Arrival Time
Burst Time
P1
12
P2
2
4
P3
3
6
P4
8
5

The Correct Answer and Explanation is :

To solve this problem, we will break it down step by step using the Shortest Remaining Time First (SRTF) scheduling algorithm, which is preemptive. We will also calculate the waiting time, turnaround time, response time, and average values for each of the processes.

1. Process Information:

  • P1: Arrival Time = 12 ms, Burst Time = 4 ms
  • P2: Arrival Time = 2 ms, Burst Time = 4 ms
  • P3: Arrival Time = 3 ms, Burst Time = 6 ms
  • P4: Arrival Time = 8 ms, Burst Time = 5 ms

Step-by-step execution of the SRTF scheduling algorithm:

Gantt Chart:

The SRTF scheduling algorithm selects the process with the shortest remaining burst time at every decision point, preempting the current running process if needed. The execution order changes dynamically as new processes arrive, and the algorithm adjusts for the shortest remaining time at that moment.

Here’s how the processes are executed:

  • At time 0, process P2 arrives and starts executing since it has the shortest burst time of 4 ms.
  • At time 3, process P3 arrives, and the remaining burst time of P2 is 1 ms (it still has the shortest time) so it keeps executing.
  • At time 8, P4 arrives, and P2 still has the shortest remaining time, so it continues to execute until time 9 when it finishes.
  • At time 9, P4 executes as it has 5 ms burst time left, and after that, the shortest time is for P3, which executes next.
  • After P3 finishes, the remaining time for P1 is executed.

This process will be represented on the Gantt chart.

Waiting Time:

The waiting time for a process is calculated as the total time it spends waiting in the ready queue before being executed.

Turnaround Time:

The turnaround time is the total time from the arrival of the process until it completes its execution (i.e., Completion Time – Arrival Time).

Response Time:

The response time is the time from the arrival of the process until it starts executing for the first time.

Average Times:

  • Average Waiting Time = Total Waiting Time / Number of Processes
  • Average Turnaround Time = Total Turnaround Time / Number of Processes

Let me compute the Gantt chart, the times for each process, and the averages.

I’ll now generate the image of the Gantt chart and perform the necessary calculations.

Here’s the breakdown of the process execution along with the calculations:

Gantt Chart:

  • The Gantt chart above represents the order in which the processes are executed, following the Shortest Remaining Time First (SRTF) algorithm.

Waiting Time:

  • P1: 4 ms
  • P2: 3 ms
  • P3: 5 ms
  • P4: 1 ms

Turnaround Time:

  • P1: 8 ms
  • P2: 7 ms
  • P3: 11 ms
  • P4: 6 ms

Average Waiting Time:

The average waiting time is:
[
\text{Average Waiting Time} = \frac{4 + 3 + 5 + 1}{4} = 3.25 \, \text{ms}
]

Average Turnaround Time:

The average turnaround time is:
[
\text{Average Turnaround Time} = \frac{8 + 7 + 11 + 6}{4} = 8.0 \, \text{ms}
]

Response Time:

The response time for each process (time from arrival to first execution):

  • P1: 12 ms (starts at 12)
  • P2: 2 ms (starts at 0)
  • P3: 3 ms (starts at 4)
  • P4: 8 ms (starts at 9)

These calculations help to understand the performance and scheduling behavior of the processes under the SRTF preemptive algorithm.

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