An organic compound has the formula CH3NO. How many valence electrons does this molecule have? Choose one: O 10 O 16 O 18 O 22 Part 2 (1 point) In order to draw a Lewis structure for CH3NO, you need to consider the relative placement of the atoms Rank the elements in decreasing order of the number of bonds each typically forms as a neutral element. Correct Answer List Question List (4 items) Drae anddronlonthe anncooriate areal 13/35> 10 OF 35 QUESTIONS COMPLETED Chapter 4 03/20/19 1734 crnvaa@mimsIntsu edu幸 In order to draw a Lewis structure for CHyNO, you need to consider the relative placement of the atoms Rank the elements in decreasing order of the number of bonds each typically forms as a neutral element. Correct Answer List Question List (4 items) Drag and drop into the appropriate area) Most bonds formed 2 K13/35 > 10 OF 35 QUESTIONS COMPLETED 03/20/19 cmvãe@mimal mtsu.edu Part 3 (1point) See Hint Draw a valid Lewis structure for the molecule CH3NO in which there are no nonzero formal charges on any of the atoms. This structure should not include any bonds between N and O Select a tool to begin drawing
The Correct Answer and Explanation is :
Part 1: Valence Electrons for CH3NO
To calculate the total number of valence electrons in CH3NO, we need to sum the valence electrons for each atom in the molecule:
- Carbon (C): 1 carbon atom × 4 valence electrons = 4 electrons
- Hydrogen (H): 3 hydrogen atoms × 1 valence electron = 3 electrons
- Nitrogen (N): 1 nitrogen atom × 5 valence electrons = 5 electrons
- Oxygen (O): 1 oxygen atom × 6 valence electrons = 6 electrons
Total valence electrons = 4 (C) + 3 (H) + 5 (N) + 6 (O) = 18 valence electrons.
Therefore, the correct answer is 18 valence electrons.
Part 2: Ranking Elements by Bonding Tendencies
The elements typically form bonds in the following order, ranked by the number of bonds they usually form as neutral atoms:
- Carbon (C): Carbon typically forms 4 bonds because it has 4 valence electrons and needs 4 more to fill its octet.
- Nitrogen (N): Nitrogen typically forms 3 bonds, as it has 5 valence electrons and needs 3 more to complete its octet.
- Oxygen (O): Oxygen typically forms 2 bonds because it has 6 valence electrons and needs 2 more to complete its octet.
- Hydrogen (H): Hydrogen typically forms 1 bond because it only needs 1 more electron to fill its shell (which is 2 electrons).
So, the order is: C > N > O > H.
Part 3: Drawing the Lewis Structure for CH3NO
Now let’s draw a valid Lewis structure for CH3NO. We need to ensure there are no formal charges on any atoms. Here’s how we proceed:
- Place the atoms: Carbon (C) is the central atom since it can form 4 bonds. Nitrogen (N) and oxygen (O) are placed on the sides. Hydrogen atoms (H) are attached to the carbon atom.
- Connect atoms with single bonds:
- Carbon (C) will form single bonds with 3 hydrogen atoms and 1 nitrogen atom.
- Nitrogen (N) will form a single bond with oxygen (O).
- Distribute the electrons:
- We have 18 valence electrons to distribute, so after the single bonds are placed, we can fill the octets of nitrogen and oxygen with lone pairs of electrons.
- No formal charges: We will adjust the bonding to ensure that there are no formal charges on any atoms.
I will now generate the Lewis structure for CH3NO.
Here is the Lewis structure for CH3NO, showing the correct bonding arrangement and placement of lone pairs. This structure ensures there are no formal charges on any of the atoms, with carbon at the center, bonded to three hydrogens, nitrogen, and oxygen. Let me know if you’d like further details or clarifications!
