Calculate the molar mass of ammonium phosphate, (NH4)3PO4

Calculate the molar mass of ammonium phosphate, (NH4)3PO4.
149.0 g/mol
113.0 g/mol
242.0 g/mol
121.0 g/mol

The Correct Answer and Explanation is :

The molar mass of ammonium phosphate, ((NH_4)_3PO_4), can be calculated by adding the molar masses of all the atoms in the formula.

  1. Ammonium ion ((NH_4^+)): The molar mass of nitrogen (N) is approximately 14.01 g/mol, and the molar mass of hydrogen (H) is approximately 1.008 g/mol. The ammonium ion has one nitrogen atom and four hydrogen atoms, so:
    [
    \text{Molar mass of } NH_4^+ = (1 \times 14.01) + (4 \times 1.008) = 14.01 + 4.032 = 18.042 \, \text{g/mol}.
    ]
  2. Phosphate ion ((PO_4^{3-})): The molar mass of phosphorus (P) is approximately 30.97 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol. The phosphate ion consists of one phosphorus atom and four oxygen atoms, so:
    [
    \text{Molar mass of } PO_4^{3-} = (1 \times 30.97) + (4 \times 16.00) = 30.97 + 64.00 = 94.97 \, \text{g/mol}.
    ]
  3. Calculating the molar mass of ((NH_4)_3PO_4): There are three ammonium ions, so the contribution from ammonium is:
    [
    3 \times 18.042 = 54.126 \, \text{g/mol}.
    ]
    The total molar mass of ammonium phosphate is then the sum of the contributions from the ammonium ions and the phosphate ion:
    [
    54.126 \, \text{g/mol} + 94.97 \, \text{g/mol} = 149.096 \, \text{g/mol}.
    ]

Therefore, the molar mass of ammonium phosphate ((NH_4)_3PO_4) is approximately 149.0 g/mol, and the correct answer is 149.0 g/mol.

Let me also generate an image to visualize this explanation.

Here’s the diagram showing the molar mass calculation for ammonium phosphate ((NH_4)_3PO_4). It visualizes the individual components and the final molar mass of 149.0 g/mol. Let me know if you need any further clarifications!

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