Convert 25 Celsius Degrees To Equivalent Degrees Fahrenheit, Degrees Rakine And Degrees Kelvin 2. A Spring-Type Scale Is Used To Weigh A Sample On The Moon. If The Value Of G Is 1/6 Of Earth’s Gravity And The “Standard” Weights (Earth Weights) Add Up To 20 Lb, What Is The Mass Of The Body?
The Correct Answer and Explanation is :
1. Conversion of 25°C to Equivalent Temperatures:
- Fahrenheit (°F):
( 25^\circ C \times \frac{9}{5} + 32 = 77^\circ F ) - Rankine (°R):
( (25 + 273.15) \times \frac{9}{5} = 536.67^\circ R ) - Kelvin (K):
( 25 + 273.15 = 298.15 \, K )
2. Mass of the Body on the Moon:
- Given that the gravitational acceleration on the Moon is 1/6th that of Earth’s, the weight of the body on the Moon is reduced. The standard weight on Earth is 20 pounds.
- On Earth, the weight in newtons is:
( 20 \, lbs \times 4.44822 = 88.9644 \, N ) - The mass of the body on Earth is:
( \text{Mass} = \frac{88.9644}{9.8} = 9.078 \, \text{kg} ) - Since mass is constant and doesn’t change with location, the mass of the body on the Moon is 9.078 kg.
This means that even though the body’s weight on the Moon is less due to reduced gravity, the mass remains the same as it would on Earth.
I’ll now generate an image summarizing these concepts!
Here is the educational diagram summarizing the conversions and mass calculation. It visually represents the conversion of 25°C to Fahrenheit, Rankine, and Kelvin, along with the explanation of the mass on the Moon. Let me know if you’d like further details!
