The overall equation involved in photosynthesis is CO2 + H2O C6H12O6 + O2 [unbalanced] If there is more than enough water, how many grams of glucose (C6H12O6, M = 180.18 g/mol) form when 4.40 g of CO2 (M = 44.01 g/mol) react

The overall equation involved in photosynthesis is CO2 + H2O C6H12O6 + O2 [unbalanced] If there is more than enough water, how many grams of glucose (C6H12O6, M = 180.18 g/mol) form when 4.40 g of CO2 (M = 44.01 g/mol) react? Report your answer with the correct sig figs. [30 pts.] 4) A compound is found to contain 23.3 mass % magnesium, 30.7 mass % sulfur, and 46.0 mass % oxygen. What is the empirical formula of this compound? (MMg = 24.31 g/mol, Ms = 32.06 g/mol, Mo = 16.00 g/mol)

The Correct Answer and Explanation is :

Answers:

1) Mass of glucose (C₆H₁₂O₆) formed = 3.00 g (rounded to 3 significant figures)

2) Empirical formula of the compound = MgSO₃


Explanation:

Photosynthesis Calculation:

The overall balanced equation for photosynthesis is:

[
6CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2
]

  • Given 4.40 g of CO₂, we first determine moles of CO₂:
    [
    \text{Moles of CO₂} = \frac{\text{Mass of CO₂}}{\text{Molar mass of CO₂}} = \frac{4.40 \text{ g}}{44.01 \text{ g/mol}} = 0.09998 \text{ moles CO₂}
    ]
  • From the balanced reaction, 6 moles of CO₂ produce 1 mole of glucose:
    [
    \text{Moles of glucose} = \frac{0.09998}{6} = 0.016663 \text{ moles C₆H₁₂O₆}
    ]
  • Converting to grams:
    [
    \text{Mass of glucose} = 0.016663 \times 180.18 \text{ g/mol} = 3.00 \text{ g}
    ]

Thus, 3.00 g of glucose is formed when 4.40 g of CO₂ reacts.


Empirical Formula Calculation:

Given mass percentages:

  • Magnesium (Mg) = 23.3%
  • Sulfur (S) = 30.7%
  • Oxygen (O) = 46.0%

Assuming a 100 g sample, convert mass to moles:
[
\text{Moles of Mg} = \frac{23.3}{24.31} = 0.958
]
[
\text{Moles of S} = \frac{30.7}{32.06} = 0.958
]
[
\text{Moles of O} = \frac{46.0}{16.00} = 2.875
]

To find the simplest whole-number ratio, divide all by the smallest value (0.958):

[
\frac{0.958}{0.958} = 1
]
[
\frac{0.958}{0.958} = 1
]
[
\frac{2.875}{0.958} \approx 3
]

Thus, the empirical formula is MgSO₃.

Now, I will generate an image representing the photosynthesis reaction.

I have provided an image illustrating the photosynthesis process, including the balanced equation and key elements such as carbon dioxide intake, water absorption, glucose production, and oxygen release. Let me know if you need any modifications!

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