calculate the molar mass of Al2(CO3)3
The Correct Answer and Explanation is :
The molar mass of a compound is calculated by adding together the atomic masses of each element present in the formula, multiplied by the number of atoms of that element in the formula. For ( \text{Al}_2(\text{CO}_3)_3 ), aluminum sulfate, we can calculate the molar mass as follows:
- Aluminum (( \text{Al} )): The atomic mass of aluminum is approximately 26.98 g/mol. There are 2 atoms of aluminum in the formula:
[
2 \times 26.98 \, \text{g/mol} = 53.96 \, \text{g/mol}
] - Carbon (( \text{C} )): The atomic mass of carbon is about 12.01 g/mol. There are 3 carbonate groups (( \text{CO}_3 )), each containing 1 carbon atom:
[
3 \times 12.01 \, \text{g/mol} = 36.03 \, \text{g/mol}
] - Oxygen (( \text{O} )): The atomic mass of oxygen is approximately 16.00 g/mol. Each carbonate group contains 3 oxygen atoms, and there are 3 carbonate groups:
[
3 \times 3 \times 16.00 \, \text{g/mol} = 144.00 \, \text{g/mol}
]
Adding these together, the total molar mass of ( \text{Al}_2(\text{CO}_3)_3 ) is:
[
53.96 \, \text{g/mol} + 36.03 \, \text{g/mol} + 144.00 \, \text{g/mol} = 233.99 \, \text{g/mol}
]
This calculation shows how the molar mass of a compound is directly linked to its molecular formula, providing insights into its chemical properties. Each element’s atomic mass contributes to the overall mass of the compound, highlighting the importance of understanding chemical formulas when studying substances’ molecular characteristics. This is crucial for applications in chemistry ranging from stoichiometric calculations in reactions to the preparation of solutions with precise concentrations.
Now, I will generate an image that visually represents the molecule Al2(CO3)3.
Here is an illustration representing the molecular structure of ( \text{Al}_2(\text{CO}_3)_3 ) (aluminum carbonate). Each atom type is color-coded for clarity: aluminum is in silver, carbon in black, and oxygen in red. This visual aids in understanding how the atoms are arranged and bonded in this compound.
