What is the correct IUPAC name for Cr2(SO4)3
The Correct Answer and Explanation is :
Correct IUPAC Name:
The correct IUPAC name for Cr₂(SO₄)₃ is Chromium(III) sulfate.
Explanation:
The compound Cr₂(SO₄)₃ consists of chromium (Cr) and the sulfate ion (SO₄²⁻). To name it correctly, we follow the IUPAC rules for naming ionic compounds.
Step 1: Identify the Cation and Its Oxidation State
- Chromium (Cr) is a transition metal, which means it can have multiple oxidation states.
- The sulfate ion (SO₄²⁻) has a charge of -2.
- Since there are three sulfate ions in the formula, the total negative charge is 3 × (-2) = -6.
- There are two chromium (Cr) atoms in the formula, so let’s assign an oxidation number x to each chromium atom: [
2(x) + 3(-2) = 0
]
[
2x – 6 = 0
]
[
2x = 6
]
[
x = +3
]
Thus, the oxidation state of chromium in this compound is +3.
Step 2: Naming the Cation
Since chromium has a +3 charge, we indicate this using Roman numerals in parentheses: Chromium(III).
Step 3: Naming the Anion
The anion present is sulfate (SO₄²⁻), which retains its name in the compound.
Final Name:
Putting it together, the correct IUPAC name is Chromium(III) sulfate.
This naming follows standard IUPAC conventions for transition metal compounds, where the oxidation state of the metal is explicitly mentioned.
Now, I will generate an image representing Chromium(III) sulfate’s molecular structure.
Here is the 3D molecular structure of Chromium(III) sulfate (Cr₂(SO₄)₃). Let me know if you need any modifications or further explanations!