Three Resistors Connected In Parallel Have Individual Values Of 4.0, 6.0, And 10.0 Ohms Respectively

Three Resistors Connected In Parallel Have Individual Values Of 4.0, 6.0, And 10.0 Ohms Respectively. If This Combination Is Connected In Series With A 12.0V Battery And A 2.0- Ohm Resistor, 2.02 12 V 4.0.2 36.00 310.00 What Is The Equivalent Resistance? (Select) What Is The Current In The 10-Ohm Resistor? (Select] What Is Power Produced By The Battery? 1 [

A) 1.82

3.94

22.0

2.55

B)0.39

0.59

0.65

0.29

C)3.0

12

37

24

The Correct Answer and Explanation is :

Solution Explanation

We have three resistors connected in parallel with values:

  • ( R_1 = 4.0 )Ω
  • ( R_2 = 6.0 )Ω
  • ( R_3 = 10.0 )Ω

This parallel combination is then connected in series with a ( 2.0 )Ω resistor and a 12.0V battery.

Step 1: Find the Equivalent Resistance of the Parallel Resistors

The formula for equivalent resistance in a parallel circuit is:

[
\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}
]

[
\frac{1}{R_{\text{eq}}} = \frac{1}{4.0} + \frac{1}{6.0} + \frac{1}{10.0}
]

[
= 0.25 + 0.1667 + 0.10
]

[
= 0.5167
]

[
R_{\text{eq}} = \frac{1}{0.5167} \approx 1.93Ω
]

Step 2: Find the Total Resistance in the Circuit

Since the parallel combination is in series with a 2.0Ω resistor, the total resistance is:

[
R_{\text{total}} = R_{\text{eq}} + R_{\text{series}}
]

[
R_{\text{total}} = 1.93Ω + 2.0Ω = 3.93Ω
]

Thus, the equivalent resistance is 3.94Ω (rounded).

Step 3: Find the Total Current Using Ohm’s Law

Ohm’s Law states:

[
V = IR
]

[
I_{\text{total}} = \frac{V}{R_{\text{total}}} = \frac{12.0V}{3.94Ω} \approx 3.05A
]

Step 4: Find the Current in the 10Ω Resistor

Using the current division formula for parallel circuits:

[
I_{10Ω} = I_{\text{total}} \times \frac{R_{\text{eq}}}{R_3}
]

[
I_{10Ω} = 3.05A \times \frac{1.93Ω}{10Ω} \approx 0.59A
]

Thus, the current in the 10Ω resistor is 0.59A.

Step 5: Find the Power Produced by the Battery

Power is given by:

[
P = VI
]

[
P = 12V \times 3.05A = 36.6W
]

Thus, the power produced by the battery is 37W (rounded).

Final Answers

  1. Equivalent Resistance: 3.94Ω
  2. Current in the 10Ω Resistor: 0.59A
  3. Power Produced by the Battery: 37W

Now, I will generate an image representing the circuit diagram.

I’ve provided the schematic circuit diagram as per the calculations. Let me know if you need any modifications or further explanations!

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