Calculate the molarity of (mol/L) of 3% hydrogen peroxide and record

Calculate the molarity of (mol/L) of 3% hydrogen peroxide and record it in Data Table 2. The term “3% concentration” is a weight-to-weight measurement, which means that there are 3 g solute per 100 g solvent. The molar mass of hydrogen peroxide is 34.01 g/mol and the density of the solution is 1.01 g/mL.

The Correct Answer and Explanation is :

The molarity of a 3% hydrogen peroxide solution is approximately 0.891 mol/L.

Explanation:

To calculate the molarity (mol/L) of a 3% hydrogen peroxide solution, we follow these steps:

  1. Mass of Solution:
    The 3% concentration means that there are 3 grams of hydrogen peroxide (H₂O₂) per 100 grams of solution. For simplicity, we assume a 1-liter solution (1000 mL). Given that the density of the solution is 1.01 g/mL, the mass of the entire solution in 1 liter is calculated as: [
    \text{Mass of solution} = \text{density} \times \text{volume} = 1.01 \, \text{g/mL} \times 1000 \, \text{mL} = 1010 \, \text{grams}
    ]
  2. Mass of Hydrogen Peroxide:
    Since the solution is 3% H₂O₂ by weight, the mass of hydrogen peroxide in the 1-liter solution is: [
    \text{Mass of H₂O₂} = \frac{3}{100} \times 1010 \, \text{g} = 30.3 \, \text{g}
    ]
  3. Moles of Hydrogen Peroxide:
    To calculate the number of moles of H₂O₂, we use its molar mass, which is 34.01 g/mol. Thus, the number of moles of H₂O₂ in the solution is: [
    \text{Moles of H₂O₂} = \frac{30.3 \, \text{g}}{34.01 \, \text{g/mol}} \approx 0.891 \, \text{mol}
    ]
  4. Molarity of Hydrogen Peroxide:
    Molarity is defined as moles of solute per liter of solution. Therefore, for a 1-liter solution: [
    \text{Molarity} = \frac{0.891 \, \text{mol}}{1 \, \text{L}} = 0.891 \, \text{mol/L}
    ]

This gives us the molarity of the hydrogen peroxide solution as approximately 0.891 mol/L.

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