Explain public static void main(String args[]) in Java?
The correct answer and explanation is :
In Java, the method signature public static void main(String[] args) serves as the entry point for program execution. Let’s break down each component:
public: This access modifier allows themainmethod to be accessible from any other class. It’s essential because the Java Runtime Environment (JRE) needs to invoke this method from outside the class where it’s defined.static: This keyword indicates that themainmethod belongs to the class itself, rather than instances of the class. As a result, the JRE can call this method without creating an object of the class.void: This return type signifies that themainmethod does not return any value.main: This is the name of the method. The JRE looks for a method namedmainto start program execution.String[] args: This parameter is an array ofStringobjects that can accept command-line arguments passed to the program when it’s executed. For example, if the program is run withjava MyClass arg1 arg2, thenargs[0]would be"arg1"andargs[1]would be"arg2".
The main method’s signature is predefined, and the JRE specifically looks for this method to begin execution. While it’s possible to overload the main method (i.e., create multiple methods named main with different parameters), the JRE will always call the version with the exact signature public static void main(String[] args) to start the program.
Understanding this method signature is fundamental for any Java programmer, as it establishes the starting point for program execution and allows for the handling of command-line arguments.