A car accelerates uniformly from rest to a speed of 23.7 km/h in 6.5 s

A car accelerates uniformly from rest to a speed of 23.7 km/h in 6.5 s. Find the distance the car travels during this time.

The correct answer and explanation is :

To find the distance the car travels during this time, we can use the equations of uniformly accelerated motion. Specifically, we can use the formula:

[
d = v_i t + \frac{1}{2} a t^2
]

Where:

  • (d) is the distance traveled,
  • (v_i) is the initial velocity,
  • (a) is the acceleration,
  • (t) is the time.

Step 1: Analyze the given information

  • The car accelerates from rest, so the initial velocity (v_i = 0 \, \text{m/s}).
  • The final velocity is given as 23.7 km/h. To use consistent units (meters per second), we need to convert the speed into m/s:

[
23.7 \, \text{km/h} = 23.7 \times \frac{1000}{3600} \, \text{m/s} = 6.583 \, \text{m/s}
]

  • The time is given as 6.5 seconds.

Step 2: Calculate the acceleration

Since the car starts from rest, the acceleration can be found using the formula for uniform acceleration:

[
v_f = v_i + a t
]

Where:

  • (v_f) is the final velocity,
  • (v_i) is the initial velocity (0 m/s),
  • (a) is the acceleration,
  • (t
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