If a DNA double helix that is 100 base pairs in length has 32 adenines

If a DNA double helix that is 100 base pairs in length has 32 adenines, how many cytosines, guanines, and thymines must it have?

The correct answer and explanation is :

To solve this question, we must understand base pairing rules in DNA and apply simple arithmetic.


🧬 Correct Answer:

  • Thymine (T): 32
  • Guanine (G): 36
  • Cytosine (C): 36

🔍 Explanation (300+ words):

DNA (deoxyribonucleic acid) is a double-stranded molecule composed of two complementary strands that form a double helix. The building blocks of DNA are nucleotides, each containing a nitrogenous base. There are four types of bases in DNA:

  • Adenine (A)
  • Thymine (T)
  • Guanine (G)
  • Cytosine (C)

In DNA, the base pairing rules (known as Chargaff’s rules) state:

  • A pairs with T (A = T)
  • G pairs with C (G = C)

This means the amount of adenine will always be equal to thymine, and the amount of guanine will always be equal to cytosine in a double-stranded DNA molecule.

Now, let’s analyze the question:

  • The DNA double helix has 100 base pairs, meaning there are 100 A-T pairs and G-C pairs total.
  • Since each base pair includes two bases (one from each strand), the molecule contains 200 individual nucleotides.
  • The number of base pairs = 100, so:
    [
    A-T \text{ pairs} + G-C \text{ pairs} = 100
    ]

We are told that the DNA has 32 adenines (A).

Since A pairs with T, there must also be 32 thymines (T).

So:

  • A-T pairs = 32
  • That accounts for 32 base pairs.

This means the remaining base pairs must be G-C pairs:
[
100 \text{ total base pairs} – 32 \text{ A-T pairs} = 68 \text{ G-C pairs}
]

Thus:

  • Guanines (G) = 34
  • Cytosines (C) = 34

Oops! Earlier, we said 36 of each — let’s fix that!

Correction:

  • A = 32
  • T = 32
  • G = 34
  • C = 34

Final Answer:

  • Thymine = 32
  • Guanine = 34
  • Cytosine = 34

The earlier values of 36 were a miscalculation — thanks for catching that!

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