Use VSEPR theory to predict the electron-pair geometry and the molecular geometry of xenon tetrafluoride

Use VSEPR theory to predict the electron-pair geometry and the molecular geometry of xenon tetrafluoride, XeF4.
Select one:
a. The electron-pair geometry is octahedral, the molecular geometry is square-planar.
b. The electron-pair geometry is tetrahedral, the molecular geometry is octahedral.
c. The electron-pair geometry is square-planar, the molecular geometry is tetrahedral.
d. The electron-pair geometry is tetrahedral, the molecular geometry is tetrahedral.
e. The electron-pair geometry is octahedral, the molecular geometry is tetrahedral.

The correct answer and explanation is :

The correct answer is:
a. The electron-pair geometry is octahedral, the molecular geometry is square-planar.


Detailed Explanation (300+ words):

To solve this question using Valence Shell Electron Pair Repulsion (VSEPR) theory, we first need to determine the Lewis structure of xenon tetrafluoride (XeF₄):

  1. Step 1: Find the number of valence electrons:
  • Xenon (Xe) is a noble gas in group 18 and has 8 valence electrons.
  • Each fluorine (F) atom is in group 17 and has 7 valence electrons.
  • Since there are four fluorine atoms, total fluorine electrons = 4 × 7 = 28 electrons.
  • Total = 8 (Xe) + 28 (F) = 36 valence electrons.
  1. Step 2: Arrange the atoms:
  • Xenon is the central atom, and four fluorines are placed around it.
  1. Step 3: Form bonds:
  • Each Xe–F bond uses 2 electrons.
  • 4 bonds × 2 electrons = 8 electrons used for bonding.
  1. Step 4: Distribute remaining electrons:
  • 36 total electrons – 8 bonding electrons = 28 electrons left.
  • Each F atom needs 6 electrons (3 lone pairs) to complete its octet: 4 × 6 = 24 electrons used for fluorines.
  • Remaining electrons: 28 – 24 = 4 electrons, which are placed on xenon as two lone pairs.
  1. Step 5: Predict electron-pair and molecular geometry:
  • Xenon has 4 bonding pairs (to fluorines) and 2 lone pairs.
  • In VSEPR theory, 6 regions of electron density (4 bonds + 2 lone pairs) around the central atom form an octahedral electron-pair geometry.
  • However, only the positions of the atoms determine the molecular geometry.
  • Because the two lone pairs occupy opposite positions (to minimize repulsion), the molecular shape becomes square planar—the four fluorine atoms are at the corners of a square, and lone pairs are above and below the plane.

Final Summary:

  • Electron-pair geometry: Octahedral (because there are 6 regions of electron density).
  • Molecular geometry: Square planar (because 2 of the 6 regions are lone pairs, leaving 4 fluorine atoms in a square plane).

Thus, option (a) is the correct choice.


Scroll to Top