Choose the best Lewis structure for NH4

Choose the best Lewis structure for NH4

A)
B) H-N-H
C)
D)
E)
14) Ca

The Correct Answer Explanation is:

The correct Lewis structure for NH₄⁺ (ammonium ion) is:

A)

         H
         |
     H - N⁺ - H
         |
         H

This structure shows a nitrogen (N) atom in the center, forming four single covalent bonds with four hydrogen (H) atoms. The structure also carries a +1 formal charge, making it the ammonium ion (NH₄⁺).


Explanation (300+ words)

The ammonium ion (NH₄⁺) is a positively charged polyatomic ion. To construct the correct Lewis structure, we follow these steps:


1. Count the total valence electrons:

  • Nitrogen (N) has 5 valence electrons.
  • Each hydrogen (H) has 1 valence electron.
  • Total electrons from atoms = 5 (N) + 4×1 (H) = 9 electrons.
  • Since the molecule has a +1 charge, we subtract 1 electron.
  • So, total electrons = 9 – 1 = 8 valence electrons to distribute.

2. Draw the skeleton structure:

  • Place nitrogen (N) at the center, with four hydrogen atoms (H) around it.
         H
         |
     H - N - H
         |
         H

3. Distribute electrons as bonds:

  • Each N–H bond requires 2 electrons.
  • 4 bonds × 2 electrons = 8 electrons used — which matches our total.

All electrons are used to form bonds, and there are no lone pairs on the nitrogen.


4. Formal charges:

Let’s calculate formal charge on nitrogen:

  • Valence electrons of N = 5
  • Bonding electrons shared = 8 (in 4 bonds) → 4 owned by N
  • Formal charge = 5 – 4 = +1

Each hydrogen has a formal charge of 0.

So, the entire NH₄⁺ ion has a net charge of +1, which matches the ion’s charge.


Why the others are incorrect:

Option B), showing “H–N–H”, only accounts for 2 hydrogen atoms and 2 bonds, which is incomplete for NH₄⁺. Other options are either blank or incomplete and do not correctly represent the structure or charge of the ammonium ion.


Conclusion:

The correct Lewis structure for NH₄⁺ is a central nitrogen atom bonded to four hydrogen atoms, with a +1 overall charge. There are no lone pairs on nitrogen, and the octet rule is satisfied. Therefore, Option A is correct

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