Draw the Lewis structure of BH3.

Draw the Lewis structure of BH3.

The Correct Answer and Explanation is:

Correct Lewis Structure for BH₃:

To draw the correct Lewis structure for borane (BH₃):

  1. Place the boron (B) atom in the center since hydrogen (H) can form only one bond and cannot be the central atom.
  2. Attach three hydrogen atoms to the boron atom using single bonds.
  3. Do not add lone pairs to hydrogen, as each hydrogen only needs 2 electrons (1 bond).
  4. Boron will have only 6 electrons (3 bonds), which is an exception to the octet rule.

Lewis Structure:

      H
      |
H — B — H

Each line represents a bonding pair of electrons.


Explanation

The Lewis structure of BH₃ (borane) illustrates the bonding arrangement between boron and hydrogen atoms. BH₃ is a molecule composed of one boron (B) atom and three hydrogen (H) atoms. To draw the Lewis structure, we begin by determining the number of valence electrons:

  • Boron (Group 13): 3 valence electrons
  • Hydrogen (Group 1): 1 valence electron × 3 = 3
  • Total = 3 (B) + 3 (H) = 6 valence electrons

In the Lewis structure, the boron atom is placed at the center with three single bonds connecting it to three hydrogen atoms. Each single bond (B–H) consists of 2 electrons. Thus, 3 bonds use all 6 available valence electrons.

Hydrogen atoms follow the duet rule, meaning they are stable with 2 electrons (1 bond). Each H atom in BH₃ forms a single bond with B, which satisfies this requirement.

Boron, however, is an exception to the octet rule. In BH₃, boron has only 6 electrons around it (3 single bonds), making it electron-deficient. It does not have a complete octet, but this is acceptable for boron compounds, especially in small molecules like BH₃.

This electron deficiency makes BH₃ highly reactive; it often acts as a Lewis acid, meaning it can accept a pair of electrons to complete its octet. In chemistry, BH₃ is often seen in reactions where it forms adducts with Lewis bases.

In summary, the Lewis structure for BH₃ is a simple molecule with three B–H bonds and no lone pairs. It illustrates key concepts such as exceptions to the octet rule and the stability of hydrogen with only two electrons.

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