print(“HUG”) STATUS NOT SUBMITTED SAVE SUBMIT INSTRUCTIONS 1 age = in

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print(“HUG“) STATUS NOT SUBMITTED SAVE SUBMIT INSTRUCTIONS 1 age = int(input(“How old are you turning? “)) 2 i = 0 RUN CODE 3 4 while (i <= “age”): 5 print(“HUG“) 6 i = i + 1 7 8 hp

The Correct Answer and Explanation is:

✅ Corrected Code

age = int(input("How old are you turning? "))
i = 0

while i < age:
    print("**HUG**")
    i += 1

🧠 Explanation

The provided code intends to ask the user for their age and then print "**HUG**" that many times—one for each year of age. However, the original version of the code contains a few key issues that prevent it from running properly or as expected.

❌ Problems in the Original Code:

  1. Line 4: while (i <= "age"):
    • Here, "age" is inside quotes, so it’s treated as a string rather than a variable.
    • Comparing an integer (i) with a string ("age") causes a type error in Python.
  2. Line 6: i = i + 1
    • This line is mostly correct in logic, but using the shorthand i += 1 is a cleaner, more Pythonic way of writing it.
  3. Logic Error:
    • The original loop condition is i <= age, but since counting starts at 0, this would print "**HUG**" one more time than the value of age. For instance, if age = 5, it would print 6 times (0 to 5 inclusive).

✅ Fixes Made:

  1. Replaced "age" with the variable age (without quotes) to ensure a numeric comparison.
  2. Changed the loop condition from i <= age to i < age to prevent off-by-one errors.
  3. Used i += 1 instead of i = i + 1 for cleaner syntax.

This corrected code now correctly:

  • Prompts the user to input their age.
  • Loops exactly age times.
  • Prints "**HUG**" once per loop iteration.

This kind of repetition is often used in programming exercises to teach basic input/output and loop control.

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