Draw the Lewis structure for a dinitride(2-) ion N2^2-.

Draw the Lewis structure for a dinitride(2-) ion N2^2-.

The Correct Answer and Explanation is:

Correct Lewis Structure for Dinitride Ion (N₂²⁻):

The dinitride ion (N₂²⁻) consists of two nitrogen atoms (N) and carries a 2− charge. The correct Lewis structure is:

mathematicaCopyEdit:⁻N≡N⁻:

Structure Explanation:

  • A triple bond connects the two nitrogen atoms.
  • Each nitrogen has one lone pair.
  • The extra 2− charge is distributed as one negative charge per nitrogen atom, often shown as one lone pair with a negative formal charge on each N.

Explanation:

The Lewis structure of a molecule or ion shows how valence electrons are arranged among the atoms. For the dinitride ion, N₂²⁻, we begin by calculating the total number of valence electrons.

  • Each nitrogen atom contributes 5 valence electrons, and the ion has an extra 2 electrons due to the 2− charge.
  • Total electrons:
    5 (from N) + 5 (from N) + 2 (extra) = 12 valence electrons.

Now we determine how to arrange these electrons between the two nitrogen atoms.

To satisfy the octet rule, each nitrogen atom should ideally have 8 electrons around it (bonding + non-bonding). The most stable structure for N₂²⁻ is one with a triple bond between the nitrogen atoms:

  • Three shared pairs (6 electrons) form the triple bond.
  • The remaining 6 electrons are distributed as 3 lone pairs: one on each nitrogen atom (2 electrons each), and one more on each nitrogen to reflect the negative charges (for a total of 4 non-bonded electrons per N).

This configuration ensures:

  • Each N has a full octet: 3 bonds (6 electrons) + 1 lone pair (2 electrons) = 8 electrons.
  • The formal charge on each N is −1, resulting in a total charge of −2 for the ion.

Thus, the Lewis structure is :⁻N≡N⁻:, with one lone pair and a −1 formal charge on each nitrogen, and a triple bond between them. This structure reflects correct bonding, full octets, and the appropriate total charge.

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