When HCl reacts with NaOH, what are the products? HCl + NaOH →
The Correct Answer and Explanation is:
When hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH), the products are:
HCl + NaOH → NaCl + H₂O
Explanation
This reaction is a classic example of an acid-base neutralization reaction. In this type of reaction, an acid reacts with a base to form a salt and water.
- HCl (hydrochloric acid) is a strong acid, which means it dissociates completely in water to give hydrogen ions (H⁺) and chloride ions (Cl⁻).
- NaOH (sodium hydroxide) is a strong base, which dissociates completely to give sodium ions (Na⁺) and hydroxide ions (OH⁻).
When these two substances are mixed:
- The hydrogen ion (H⁺) from the acid reacts with the hydroxide ion (OH⁻) from the base to form water (H₂O).
- The sodium ion (Na⁺) from the base and the chloride ion (Cl⁻) from the acid remain in the solution and combine to form sodium chloride (NaCl), a common salt.
This can be shown in ionic form as:
H⁺(aq) + OH⁻(aq) → H₂O(l)
Na⁺(aq) + Cl⁻(aq) → NaCl(aq)
In a complete neutralization reaction:
- The pH of the resulting solution will be close to 7 if equal moles of acid and base are used.
- No excess acid or base remains in the solution.
This reaction is also exothermic, meaning it releases heat. That’s why the container might feel warm when the two are mixed.
Applications:
- Neutralization reactions like this are used in various real-life applications, such as treating acid spills with a base, regulating soil pH, or making salt and water in laboratory or industrial settings.
In summary, when hydrochloric acid reacts with sodium hydroxide, the result is sodium chloride (a salt) and water, following the general rule for acid-base neutralization.
