What are the two products of the reaction? H2S + KOH products
The correct Answer and Explanation is:
The reaction between hydrogen sulfide (H₂S) and potassium hydroxide (KOH) results in the formation of potassium sulfide (K₂S) and water (H₂O). The balanced chemical equation for this reaction is:
H2S+2KOH→K2S+2H2OH_2S + 2KOH \rightarrow K_2S + 2H_2O
Explanation:
This reaction is a neutralization reaction, where an acid (H₂S) reacts with a base (KOH) to form a salt (K₂S) and water. Let’s break it down:
- Nature of Reactants:
- Hydrogen sulfide (H₂S) is a weak diprotic acid. It donates hydrogen ions (H⁺) and forms sulfide (S²⁻) or bisulfide (HS⁻) in solution.
- Potassium hydroxide (KOH) is a strong base that dissociates completely in water to produce hydroxide ions (OH⁻).
- Reaction Mechanism:
- The hydroxide ions (OH⁻) from KOH react with H₂S to remove protons (H⁺), leading to the formation of water (H₂O).
- Two KOH molecules neutralize one H₂S molecule, forming potassium sulfide (K₂S) as the main product.
- Significance of the Reaction:
- Industrial Applications: Potassium sulfide is used in various chemical processes, including dyes, flotation agents, and in leather treatment.
- Environmental Implications: Since hydrogen sulfide is a toxic gas with an unpleasant odor (similar to rotten eggs), neutralizing it with KOH can be used in waste treatment to reduce its harmful effects.
