write the name of the compound with the formula MnBr2
The Correct Answer and Explanation is:
The name of the compound with the formula MnBr₂ is manganese(II) bromide.
Explanation
The compound MnBr₂ consists of two elements: manganese (Mn) and bromine (Br). To name this compound correctly, it’s important to follow the rules for naming ionic compounds containing transition metals. Manganese is a transition metal, which means it can form more than one possible charge (oxidation state). Therefore, the name must indicate the specific charge of the manganese ion in this compound.
Bromine, as a halogen, typically forms a -1 anion, known as bromide when part of a compound. Since there are two bromide ions, each with a -1 charge, the total negative charge is -2. To balance the charges in the compound, the manganese ion must have a +2 charge, making it a Mn²⁺ ion.
Thus, the compound contains Mn²⁺ and 2 Br⁻ ions. The systematic name includes the name of the metal (manganese), followed by the oxidation state in Roman numerals in parentheses, and then the name of the non-metal with an -ide ending. The correct name becomes manganese(II) bromide.
This naming method avoids ambiguity since manganese can also form a +3 ion (Mn³⁺), which would result in a different compound: manganese(III) bromide (MnBr₃). Including the Roman numeral is essential for distinguishing between these compounds.
Understanding how to name transition metal compounds involves recognizing the necessity of indicating the metal’s oxidation state due to its variable valency. Additionally, the suffix -ide is standard for naming simple binary compounds with non-metals.
Manganese(II) bromide is an example of a binary ionic compound, formed through the electrostatic attraction between positively charged metal cations and negatively charged non-metal anions. The naming conventions applied here are standardized by the International Union of Pure and Applied Chemistry (IUPAC), ensuring consistency in chemical nomenclature.
