Aspartame has the chemical formula C14H18N2O5 and undergoes combustion by the following unbalanced reaction

Aspartame has the chemical formula C14H18N2O5 and undergoes combustion by the following unbalanced reaction: C14H18N2O5 + O2 → CO2 + H2O + N2. Using bond dissociation energies, calculate the amount of energy released upon combustion of 35 pounds of aspartame: C14H18N2O5 + 1.5O2 → 4CO2 + 5H2O + N2. C-C = 347 kJ/mol, C-H = 413 kJ/mol, C-N = 305 kJ/mol, N-N = 163 kJ/mol, C=O = 799 kJ/mol, O-H = 463 kJ/mol, N-H = 391 kJ/mol. Given that aspartame is often used as a substitute for sucrose (C12H22O11), determine the heat of combustion for 35 pounds of sucrose. Compare the two values and decide which one has the higher caloric content (1 kcal = 4.184 kJ).

The Correct Answer and Explanation is:

To compare the energy released by the combustion of 35 pounds of aspartame versus 35 pounds of sucrose, first calculate the combustion energy using bond dissociation energies (BDEs).


Step 1: Molar Masses

  • Aspartame (C₁₄H₁₈N₂O₅)
    = 14(12.01) + 18(1.008) + 2(14.01) + 5(16.00) = 294.30 g/mol
  • Sucrose (C₁₂H₂₂O₁₁)
    = 12(12.01) + 22(1.008) + 11(16.00) = 342.30 g/mol

Step 2: Mass in grams

  • 35 pounds = 35 × 453.592 = 15,875.72 grams

Step 3: Moles of each substance

  • Aspartame: 15,875.72 / 294.30 ≈ 53.94 mol
  • Sucrose: 15,875.72 / 342.30 ≈ 46.38 mol

Step 4: Energy per mole via bond energies (approximate estimate)

Bonds broken (in reactants, per mole of Aspartame):

Let’s estimate approximately:

  • 14 C–H: 14 × 413 = 5782
  • 6 C–C: 6 × 347 = 2082
  • 4 C–N: 4 × 305 = 1220
  • 4 N–H: 4 × 391 = 1564
  • 5 C=O: 5 × 799 = 3995
  • 5 O–H: 5 × 463 = 2315
  • Total bonds broken (energy input)16,958 kJ/mol

Bonds formed (products):

  • 14 CO₂ (C=O): 28 C=O × 799 = 22,372
  • 9 H₂O: 18 O–H × 463 = 8,334
  • 1 N₂ (N≡N): 1 × 946 = 946
  • Total bonds formed (energy released)31,652 kJ/mol

Net energy released per mole:

31,652 − 16,958 = 14,694 kJ/mol


Step 5: Total energy for 53.94 mol Aspartame

= 53.94 × 14,694 ≈ 792,492 kJ
= 792,492 ÷ 4.184 ≈ 189,414 kcal


Step 6: Heat of combustion for sucrose (known)

Standard enthalpy of combustion for sucrose ≈ −5645 kJ/mol

  • Total energy = 46.38 × 5645 ≈ 261,773 kJ
  • In kcal = 261,773 ÷ 4.184 ≈ 62,545 kcal

Conclusion:

  • Aspartame (35 lb): ~189,414 kcal
  • Sucrose (35 lb): ~62,545 kcal

Aspartame releases significantly more energy per 35 pounds than sucrose, showing a higher caloric content by mass.

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