ILLUD U What is the mass in grams of 13.2 amu
The Correct Answer and Explanation is:
To determine the mass in grams of 13.2 moles of illudium (symbol: U), you need to use the molar mass of uranium.
Step-by-step solution:
- Know the molar mass of uranium (U):
Uranium has a molar mass of approximately 238.03 g/mol. - Use the formula: Mass (g)=Moles×Molar Mass (g/mol)\text{Mass (g)} = \text{Moles} \times \text{Molar Mass (g/mol)}Mass (g)=Moles×Molar Mass (g/mol)
- Substitute the values: Mass=13.2 mol×238.03 g/mol\text{Mass} = 13.2 \, \text{mol} \times 238.03 \, \text{g/mol}Mass=13.2mol×238.03g/mol
- Calculate the mass: Mass=3149.996 g\text{Mass} = 3149.996 \, \text{g}Mass=3149.996g
- Round appropriately: Mass≈3150 grams\text{Mass} \approx \boxed{3150 \, \text{grams}}Mass≈3150grams
Explanation
To calculate the mass in grams of a given number of moles, you must understand the relationship between moles, molar mass, and grams. This relationship is central to stoichiometry in chemistry and allows scientists to convert between the number of particles and measurable quantities like grams.
The mole is a standard scientific unit used to measure large quantities of very small entities such as atoms or molecules. One mole of any element contains approximately 6.022×10236.022 \times 10^{23}6.022×1023 particles, known as Avogadro’s number. The molar mass is the mass of one mole of a substance and is numerically equal to the element’s atomic mass in grams.
Uranium (U) has a molar mass of about 238.03 grams per mole. This means one mole of uranium weighs 238.03 grams. If you have 13.2 moles of uranium, you simply multiply the number of moles by the molar mass to get the total mass.
By multiplying 13.2 moles by 238.03 grams per mole, the result is approximately 3150 grams. This calculation allows chemists and technicians to measure out specific quantities of substances needed for reactions or other purposes. It ensures accuracy in experiments and in industrial applications where precise amounts of materials are essential. Understanding this concept is fundamental for anyone studying chemistry or working in any field that involves chemical processes.
